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viva [34]
3 years ago
11

At the equator, the radius of the Earth is approximately 6370 km. A plane flies at a very low altitude at a constant speed of v

= 239 m/s. Upon landing, the plane can produce an average deceleration of a = 16.5 m/s².
How long will it take the plane to circle the Earth at the equator?
Physics
1 answer:
Cerrena [4.2K]3 years ago
4 0

To solve this problem we will apply the concepts related to the kinematic equations of linear motion. From there we will define the distance as the circumference of the earth (approximate as a sphere). With the speed given in the statement we will simply clear the equations below and find the time.

R= 6370*10^3 m

v = 239m/s

a = 16.5m/s^2

The circumference of the earth would be

\phi = 2\pi R

Velocity is defined as,

v = \frac{x}{t}

t = \frac{x}{v}

Here x = \phi, then

t = \frac{\phi}{v} = \frac{2\pi (6370*10^3)}{239}

t = 167463.97s

Therefore will take 167463.97 s or 1 day 22 hours 31 minutes and 3.97seconds

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A certain ultrasound device can measure a fetal heart rate as low as 50 beats per minute. This corresponds to the surface of the
balu736 [363]

Answer:

The. Machine must detect a shift of

1 Hz

Explanation:

Frequency shift is given as

={ ( Vsound +V/ V sound -V) -1}f emitted

So by substitution we have

= { 1540+4E-4/1540-4E)-1) 2*10^6

= 1Hz

7 0
3 years ago
a girl pushes a cart to the left with a 100-N force. A boy pushes it to the right with a 50-N force. what is the net force exert
NNADVOKAT [17]

Answer:

50 to the left

Explanation:

150-100: 50 to the left

3 0
2 years ago
Your in an escape room. Only its real and your oxygen runs out in 3 minutes unless you solve this problem, The problem :a ball i
alex41 [277]

The sum of the series allows to find the result for the total distance that the ball bounces is:

            total distance = 59.52 in

A series is a set of things or numbers related by a specific operation.

They indicate that the ball falls from an initial height y₀ = 30 in. and it bounces 50% of the height and the process is repeated until it stops, see attached.

Let's build a table to observe the sequence.

drop   height    rebound

   1        30          15

   2       15            7.5

   3        7.5         3.75

If we call the first term y₀  

The first bounce can be found.

                             y₁ = \frac{y_o}{2}

The second bounces.

                             y_2 = \frac{y_1}{2}  \\y_2 = \frac{y_o}{4}

The third bounce.

                             y_3  = \frac{y_2}{2}  \\y_3 = \frac{y_0}{ 8}

By observing this table we can construct a series of the form

 

      Total distance = y_o \ ( 1 + \frac{1}{2} + \frac{1}{4}+  \frac{1}{8} + ... +\frac{1}{2n} )

The sum of the serie has a result of

        sum  = 127/64 = 1,984

Let's calculate

     distance total  = 30 1,984

     Distance total = 59.52 cm

In conclusion, using the sum of the series we can find the result for the total distance that the ball bounces is:

            total distance = 59.52 in

Learn more here: brainly.com/question/8879163

4 0
3 years ago
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When a wire 1.5 m long carries a 24-A current in the +x direction in a uniform external magnetic field, the magnetic force exert
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Answer:

Explanation:

Let the magnetic field be

B = B_xi +B_yj +B_z k

For magnetic force , the expression is

F = L ( I x B )

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F = 36 B_y k - 36 B_z j

Given

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Equating equal terms

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Now the direction of current is changed to y direction

so F = 1.5[ 24j \times ( B_xi +B_yj +B_z k )]

Given

F = - 3 i - 2 k

Equating equal terms

we have

B_x = 2 / 36 , B_z = - 3 / 36

So B = 2/36 i + 2/36 j - 3/ 36 k

Magnitude of B

= 4.1 / 36 T

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