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Rama09 [41]
2 years ago
5

Help help math math ASAP ASAP

Mathematics
1 answer:
Virty [35]2 years ago
6 0

Answer:

\displaystyle y = 4x + 12

Step-by-step explanation:

−4x + y = 12

+ 4x + 4x

_________

\displaystyle \boxed{y = 4x + 12}

I am joyous to assist you at any time.

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Will choose brainliest... Figure out the combination...
Finger [1]

Answer:

Its THIS ↓↓↓↓

Step-by-step explanation:

if its not this then i dk what

4 0
2 years ago
Read 2 more answers
Solve – 4(x + 6) – 6 = 4(x – 1) for x
hjlf

4Step-by-step explanation:

bhtrrerh

6 0
3 years ago
16. Which of the following are equivalent to(x) 16xA) g(r) 8.21B) g(c) 4096.16-3g (x) -4.4xD) g(x) 0.0625-16'+1E) g(x) 32.16E) g
swat32
F(x) = 16ˣ

A. g(x) = 8(2ˣ)
    g(x) = (2³)(2ˣ)
    g(x) = 2ˣ⁺³
The answer is not A.

B. g(x) = 4096(16ˣ⁻³)
    g(x) = (16³)(16ˣ⁻³)
    g(x) = 16ˣ
The answer is B.

C. g(x) = 4(4ˣ)
     g(x) = 4ˣ⁺¹
The answer is not C.

D. g(x) = 0.0625(16ˣ⁺¹)
     g(x) = (16⁻¹)(16ˣ⁺¹)
     g(x) = 16ˣ
The answer is D.

E. g(x) = 32(16ˣ⁻²)
    g(x) = (2⁵)(2⁴ˣ⁻⁸)
    g(x) = 2(⁴ˣ⁻³)
The answer is not E.

F. g(x) = 2(8ˣ)
    g(x) = 2(2³ˣ)
    g(x) = 2³ˣ⁺¹
The answer is not F.

The answer is B and D.
6 0
3 years ago
A coin is tossed 4 times. Let E1 be the event "the first toss shows heads" and E2 the event "the second toss shows heads" and so
Elden [556K]

Answer:

The events are independent.

The probability of showing heads on both toss is equal to 1/2

Step-by-step explanation:

The sample space for this experiment consists of 2⁴= 16 sample points, as each toss can result in two outcomes we assume that the events are equally likely.

Two events are independent in the sample space if the probability of one event occurs, is not affected by whether the other event has or has not occurred.

In general the k events are defined to be mutually independent if and only if the probability of the intersection of  any 2,3,--------, k  equals the product of their respective probabilities.

P (A∩B) = P(A). P(B)

P (A∩B)   = 1/2. 1/2= 1/4

                                                                  Head          Tail

 P(E1)= 1/2  ----------          Coin 1               H,H              T,H

                                                                1/4                  1/4

  P(E2)= 1/2  ---------------  Coin 2             H, H               H,T

                                                                      1/4           1/4

So the events are independent.

The probability of showing heads on both toss is equal to 1/2

The sample space for this experiment consists of 2⁴= 16 sample points, out of which eight will have heads on both toss.

Or in other words ( 1/4* 1/4) = 2/4 = 1/2

4 0
3 years ago
What is the equivalent expression of 20x + 35?​
Serjik [45]
5(4x+7) there you go uwu
6 0
3 years ago
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