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hjlf
3 years ago
9

The reason an increase in substrate concentration does not increase the reaction rate indefinitely is because

Chemistry
1 answer:
scoundrel [369]3 years ago
3 0

Answer:

Increasing substrate concentration also increases the rate of reaction to a certain point. Once all of the enzymes have bound, any substrate increase will have no effect on the rate of reaction, as the available enzymes will be saturated and working at their maximum rate.

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Convert to scientific notation : 520,000,000
PIT_PIT [208]

Answer:

5.2 x 10^8

Explanation:

3 0
3 years ago
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Sugar when dissolved into water, propose whether the compound forms atoms, molecules or lattices. Justify you answer
kirza4 [7]

Answer:

atoms

Explanation:

for sugar to dissolve in water hydaration must be equal to or greater than the lattice energy or molecular forces so when the molecular forces breaks new atoms are formed for recombination in new compound

6 0
3 years ago
True or False: Water molecules "stick together" due to hydrogen bonds.
Dimas [21]

Answer:

True

Explanation:

To begin with,

Hydrogen bonds are attractions that contain a force caused by the difference in charge. This is due to the positive hydrogen ions as well as  slightly negative ions. Therefore, hydrogen bonds make water molecules 'sticky.' To add, the attractions between hydrogen bonds are weaker than ionic and covalent bonds but strong enough to cause them to 'stick together'

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6 0
3 years ago
PLEASE HELP THIS IS WORTH 13 POINTS
inysia [295]

Answer:

The chemical reaction is a Double Displacement

Explanation:

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6 0
3 years ago
Atmospheric pressure at sea level is equal to a column of 760 mm Hg. Oxygen makes up 21 percent of the atmosphere by volume. The
Neporo4naja [7]

<u>Answer:</u> The partial pressure of oxygen is 160 mmHg

<u>Explanation:</u>

We are given:

Percent of oxygen in air = 21 %

Mole fraction of oxygen in air = \frac{21}{100}=0.21

To calculate the partial pressure of oxygen, we use the equation given by Raoult's law, which is:

p_{O_2}=p_T\times \chi_{O_2}

where,

p_{O_2} = partial pressure of oxygen = ?

p_T = total pressure of air = 760 mmHg

\chi_{O_2} = mole fraction of oxygen = 0.21

Putting values in above equation, we get:

p_{O_2}=760mmHg\times 0.21\\\\p_{O_2}=160mmHg

Hence, the partial pressure of oxygen is 160 mmHg

8 0
3 years ago
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