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mariarad [96]
2 years ago
7

The sum of two numbers is 58. Twice the second number subtracted to four times the first number is 28. Find the two numbers. ​

Mathematics
1 answer:
lakkis [162]2 years ago
5 0

Answer: The numbers are 14 2/3 and 43 1/3 (you can also write it as 44/3 and 130/3)

Step-by-step explanation:

x+y=58

2y-4x=28

This is a system of equations, so you can make the y equal to each other by: 2x+2y=116

Now you can subtract the equations from each other, so you have

2x+2y=116

-(2y-4x)=28

The y cancels out, leaving you with 6x=88, so x=14 2/3

When you plug x in, you get y=43 1/3

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Answer:

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Step-by-step explanation:

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3 years ago
Can you help me plz in number 12,13,and 14 find the sum or difference.write your answer in simplest form plz explain good so I u
Maurinko [17]

Answer:

12. 11/18-1/6=4/9

13. 2/7+2/5=24/35

14. 3/4-3/10=9/20

Step-by-step explanation:

12. 11/18-1/6

11/18-1/6=11/18-(1/6)*(3/3)

11/18-1/6=11/18-(1*3)/(6*3)

11/18-1/6=11/18-3/18

11/18-1/6=(11-3)/18

11/18-1/6=8/18

Dividing the numerator and denominator of the fraction on the right side of the equation by 2:

11/18-1/6=(8/2)/(18/2)

11/18-1/6=4/9


13. 2/7+2/5

2/7+2/5=(2/7)*(5/5)+(2/5)*(7/7)

2/7+2/5=(2*5)/(7*5)+(2*7)/(5*7)

2/7+2/5=10/35+14/35

2/7+2/5=(10+14)/35

2/7+2/5=24/35


14. 3/4-3/10

3/4-3/10=(3/4)*(5/5)-(3/10)*(2/2)

3/4-3/10=(3*5)/(4*5)-(3*2)/(10*2)

3/4-3/10=15/20-6/20

3/4-3/10=(15-6)/20

3/4-3/10=9/20

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Step-by-step explanation:

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its 24 you welcome

Step-by-step explanation:

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