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Agata [3.3K]
2 years ago
10

Kaylin buys a greeting card for $3.79. she then buys 4 postcards that all cost the same amount. the total cost is $5.11. how muc

h is each postcard. show your work
i need the answer today
Mathematics
1 answer:
Pie2 years ago
4 0

Answer:

Step-by-step explanation:

Givens

Greeting Card = 3.79

Total Cost = 5.11

Post cards = x

Equation

Total Cost = Greeting Card + 4x

Solution

Substitute the gives into the equation

5.11 = 3.79 + 4x                       Subtract 3.79 from both sides

5.11 - 3.79 = 3.79 - 3.79 + 4x  Combine

1.32 = 4x                                  Divide by 4

1.32/4 = 4x/4

x = 33

Each post card costs 0.33 dollars

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17. El precio de los terrenos en Lima es proporcional al área e inversamente proporcional a su distancia con respecto al centro
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Answer:

375000

Step-by-step explanation:

We have that in this case the following proportion would be fulfilled:

Price * Distance / area

Now, we have that for a distance of 45 km and an area of 900 m ^ 2 the price is 250,000, now for a distance of 40 km but with an area of 1,200 m ^ 2, how would the price be, we replace:

250000 * 45/900 = P * 40/1200

12500 * 1200/40 = P

P = 375000

Which means that for these conditions the price is 375000.

3 0
3 years ago
Bike rental company A charges an initial fee of $8 plus $1.25 for every hour spent biking. Bike rental company B charges $2.75 f
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2.75h =8-1.25h is thus the one
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3 years ago
The growth rate of nominal gdp between 1998 9063 <br> and 2018 20501 was
Alex73 [517]

Answer:

The nominal GDP growth rate between 1998 and 2018 was 126.20 percent.

Step-by-step explanation:

Given that in 1998 the country's GDP was $ 9,063 and in 2018 it was $ 20,501, to determine the nominal growth rate of the nation's GDP, the following calculation must be made:

9,063 = 100

20,501 = X

((20,501 x 100) / 9,063) = X

2,050,100 / 9,063 = X

226.20 = X

226.20 - 100 = 126.20

Therefore, the nominal GDP growth rate between 1998 and 2018 was 126.20 percent.

8 0
3 years ago
Find the relative extrema, if any, of the function. Use the Second Derivative Test if applicable. (If an answer does not exist,
belka [17]

Answer:

We have the function g(x) = x^3 -15*x

First, to find extrema, we can find the zeros of the first derivative.

g'(x) = 3*x^2 -15

g'(x) = 0 = 3*x^2 - 15

x^2 = 15/3 = 5

x = √5

x = -√5

Now, watching at the second derivative we have:

g''(x) = 6*x

so when we have

g''(√5) = 6*√5 > 0 then x = √5 is a local minimum

g''(-√5) = -6*√5 < 0, then x = -√5 is a local maximum.

3 0
3 years ago
A water balloon is tossed into the air with an upward velocity of 25 ft/s. Its height h(t) in ft after t seconds is given by the
iren2701 [21]
1) h (t) = -16t^2 + 25t + 3 \\ \\h(t) = 0 \\ \\ 0 = -16t^2 + 25t + 3 \\ \\ quadratic \ formula \\ \\ a = -16 \ , \ b = 25 \ , c = 3 \\ \\ t =  \frac{-25 \pm  \sqrt{25^2-4(-16)(3)} }{2(-16)} \\ \\  \frac{-25 \pm  \sqrt{625+192} }{-32} \\ \\  \frac{-25 \pm  \sqrt{817} }{-32} \\ \\  \frac{-25 \pm 28.5832}{-32} \\ \\ t =  \frac{-25 - 28.5832}{-32} \\ \\ t =  \frac{-25 + 28.5832}{-32} \\ \\  \frac{53.5832}{32} \\ \\      \frac{53.5832}{32} \\ \\  1.66447

The water ballon will hit the ground after 1.66447 seconds.

--------

2) t = 1 \\ \\ h(1) = -16(1)^2 + 25(1) + 3 \\ \\ -16 + 25 + 3 \\ \\ 12

The height will be 12 feet if t = 1 second.
6 0
3 years ago
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