Question

If 10.00 mL of the solution prepared in question 4 is used to make another 125.00 mL solution of NaCl, what is the new concentration

Answer 1

The new concentration of the solution is 0.016 M

Dilution

From the question, we are to determine the concentration of the new solution prepared from question 4.

NOTE: Question is provided below

From question 4, the concentration of the sodium chloride solution is 0.200M

Now, to determine the new concentration,

Using the dilution law

C₁V₁ = C₂V₂

Where

C₁ is the initial concentration

V₁ is the initial volume

C₂ if the final concentration

and V₂ is the final volume

Then,

C₁ = 0.200 M

V₁ = 10.00 mL
C₂ = ?

V₂ = 125.00 mL

Then,

0.200 × 10.00 = C₂ × 125.00

$C_{2}= \frac{0.200 \times 10}{125.00}$

C₂ = 0.016 M

Hence, the new concentration of the solution is 0.016 M

Question 4:

Calculate the amount of solid sodium chloride needed to make 200.00 mL of a 0.200 M solution

Learn more on Dilution here: brainly.com/question/24881505