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IRINA_888 [86]
2 years ago
5

1) Identify two different mineral nutrients present in the fertilizer

Chemistry
1 answer:
Alexxx [7]2 years ago
4 0

The two different mineral elements that a fertilizer can contain are:

  • Phosphorus - build up of nucleic acid and ATP
  • Nitrogen- synthesis of proteins

<h3>What are fertilizers?</h3>

Fertilizers are chemical substances added to the soil in order to improve crop growth and development.

Fertilizers are artificially made to contain mineral elements that are needed by the plants. Some of the mineral elements are as follows:

  • Phosphorus
  • Nitrogen
  • Pottasium

  • Phosphorus helps in the build up of nucleic acids and ATP for energy.
  • Nitrogen is useful in the synthesis of proteins.

Learn more about minerals at: brainly.com/question/18078524

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What 3 sub types of covergent plate boundaries?
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(1) Ocean to Continent
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(3)Ocean to Ocean
are the three sub types of convergent plate boundaries.
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When 120 g of carbon reacts completely with 320 g of oxygen the mass of carbon dioxide formed will be?
olga2289 [7]
440 cause mass cant be created or destroyed
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A particle with charge +1 nC (a nanocoulomb is 1 10-9 C) is located at the origin. What is the electric field due to this partic
Zolol [24]

Answer:

E=35.97\frac{V}{m}

Explanation:

The electric field of a point charge can be calculated using the next equation:

E=\frac{1}{4\pi \epsilon_0} \frac{Q}{r^2}

Where:

\epsilon_0=Absolute\hspace{3}permittivity\hspace{3}of\hspace{3}free\hspace{3}space\approx 8.85\times 10^{-12} \\Q=Charge\hspace{3}magnitude\\r=Distance

The distance can be calculated as:

r=\sqrt{0.5^2+0^2+0^2} =0.5

Using the data provided by the problem:

E=\frac{1}{4\pi (8.85\times 10^{-12}) } \frac{1\times 10^{-9} }{0.5^2} =35.96721878\approx35.97V/m

8 0
4 years ago
The water-gas shift reaction plays a central role in the chemical methods for obtaining cleaner fuels from coal: CO(g) + H2O(g)
taurus [48]

<u>Answer:</u> The concentration of carbon dioxide, hydrogen gas, carbon monoxide and water when equilibrium is re-established are 0.362 M, 0.212 M, 0.138 M and 0.138 M respectively.

<u>Explanation:</u>

For the given chemical reaction:

CO(g)+H_2O(g)\rightleftharpoons CO_2(g)+H_2(g)

The expression of K_c for above reaction follows:

K_c=\frac{[CO_2][H_2]}{[CO][H_2O]}         ........(1)

We are given:

[CO]_{eq}=[H_2O]_{eq}=[H_2]_{eq}=0.10M

[CO_2]_{eq}=0.40M

Putting values in above equation, we get:

K_c=\frac{0.40\times 0.10}{010\times 0.10}\\\\K_c=4

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Moles of hydrogen gas = 0.30 mol

Volume of solution = 2.0 L

Putting values in above equation, we get:

\text{Molarity of }H_2=\frac{0.30mol}{2L}=0.15M

When hydrogen gas is added, the concentration of product gets increased. But, by Le-Chatelier's principle, the equilibrium will shift in the direction where concentration of product must decrease, which is in the backward direction.

Concentration of hydrogen gas when equilibrium is re-established = 0.1 + 0.15 = 0.25 M

Now, the equilibrium is shifting to the reactant side. The equation follows:

                      CO(g)+H_2O(g)\rightleftharpoons CO_2(g)+H_2(g)

Initial:              0.1      0.1                 0.4       0.1

At eqllm:       0.1+x   0.1+x           0.4-x      0.25-x

Putting values in expression 1, we get:

4=\frac{(0.25-x)(0.4-x)}{(0.1+x)(0.1+x)}\\\\3x^2+1.45x-0.06=0\\\\x=0.038,-0.522

Neglecting the negative value of 'x'

Calculating the concentrations of the species:

Concentration of carbon dioxide = (0.4 - x) = (0.4 - 0.038) = 0.362 M

Concentration of hydrogen gas = (0.25 - x) = (0.25 - 0.038) = 0.212 M

Concentration of carbon monoxide = (0.1 + x) = (0.1 + 0.038) = 0.138 M

Concentration of water = (0.1 + x) = (0.1 + 0.038) = 0.138 M

Hence, the concentration of carbon dioxide, hydrogen gas, carbon monoxide and water when equilibrium is re-established are 0.362 M, 0.212 M, 0.138 M and 0.138 M respectively.

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4 years ago
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