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jolli1 [7]
2 years ago
7

Please help me with this!!! ​

Mathematics
1 answer:
Strike441 [17]2 years ago
7 0

Answer:

See explanation below

Step-by-step explanation:

Let's use Q10 as an example and you will work on Q11-12 as they are the same.

I believe the middle column (5x-4) wants you to substitute the given x, so:

Q10.1: 5(-2)-4

Q10.2: 5(4)-4

Q10.3: 5(0)-4

Q10.4: 5(1)-4

The right most column (f(x)) should be asking you the answers from your middle column, so:

Q10.1: -14

Q10.2: 16

Q10.3: -4

Q10.4: 1

As for the domain and range, let's define these two names in case you haven't learnt them:

Domain: What reasonable x values can be inputted into the function.

Range: What reasonable results will be shown after calculating.

In these case, you can input any real numbers into x as you like into the function, the results will always be other real numbers.

Hence, for Q10-12, D and R should be "All real numbers"

Just some extra info, Let the function f(x) be \frac{1}{x+1}. Since the denominator cannot be 0 in a fraction, we say that the domain of x is "All real numbers except -1" as -1+1 = 0 and \frac{1}{0} is undefined.

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N + 6f (n = 9 and f= 3)
Vesna [10]

Answer:

27

Step-by-step explanation:

sub in the letters with the given number in brackets

= (9) + 6(3)

= (9) + 18

= 27

5 0
3 years ago
A researcher wants to see if birds that build larger nests lay larger eggs. He selects two random samples of nests: one of small
True [87]

Answer:

95% confidence interval for the difference between the average mass of eggs in small and large nest is between a lower limit of 0.81 and an upper limit of 2.39.

Step-by-step explanation:

Confidence interval is given by mean +/- margin of error (E)

Eggs from small nest

Sample size (n1) = 60

Mean = 37.2

Sample variance = 24.7

Eggs from large nest

Sample size (n2) = 159

Mean = 35.6

Sample variance = 39

Pooled variance = [(60-1)24.7 + (159-1)39] ÷ (60+159-2) = 7619.3 ÷ 217 = 35.11

Standard deviation = sqrt(pooled variance) = sqrt(35.11) = 5.93

Difference in mean = 37.2 - 35.6 = 1.6

Degree of freedom = n1+n2 - 2 = 60+159-2 = 217

Confidence level = 95%

Critical value (t) corresponding to 217 degrees of freedom and 95% confidence level is 1.97132

E = t×sd/√(n1+n2) = 1.97132×5.93/√219 = 0.79

Lower limit = mean - E = 1.6 - 0.79 = 0.81

Upper limit = mean + E = 1.6 + 0.79 = 2.39

95% confidence interval for the difference in average mass is (0.81, 2.39)

3 0
3 years ago
5. On a family vacation Amy's dad drove the car at a constant speed and traveled 585 miles in 13 hours. At this rate , how long
Nikitich [7]

Answer:

cars rate of speed: 45 mph

Part B: d=45t

Step-by-step explanation: d=rt formula

r=45

585/13=45

3 0
3 years ago
Please i need this answer right now !!!! Dx
yaroslaw [1]

Answer: the answer is d sin30degrees equal 5/x because sin is opposite over hyponuese

8 0
3 years ago
Quadratic equations are never used to solve word problems. True or false?
mel-nik [20]
Quadratic equations CAN be used to solve word problems so the answer to your question is false
7 0
3 years ago
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