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jolli1 [7]
2 years ago
7

Please help me with this!!! ​

Mathematics
1 answer:
Strike441 [17]2 years ago
7 0

Answer:

See explanation below

Step-by-step explanation:

Let's use Q10 as an example and you will work on Q11-12 as they are the same.

I believe the middle column (5x-4) wants you to substitute the given x, so:

Q10.1: 5(-2)-4

Q10.2: 5(4)-4

Q10.3: 5(0)-4

Q10.4: 5(1)-4

The right most column (f(x)) should be asking you the answers from your middle column, so:

Q10.1: -14

Q10.2: 16

Q10.3: -4

Q10.4: 1

As for the domain and range, let's define these two names in case you haven't learnt them:

Domain: What reasonable x values can be inputted into the function.

Range: What reasonable results will be shown after calculating.

In these case, you can input any real numbers into x as you like into the function, the results will always be other real numbers.

Hence, for Q10-12, D and R should be "All real numbers"

Just some extra info, Let the function f(x) be \frac{1}{x+1}. Since the denominator cannot be 0 in a fraction, we say that the domain of x is "All real numbers except -1" as -1+1 = 0 and \frac{1}{0} is undefined.

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Answer:

48:29

Step-by-step explanation:

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When writing the ratio we write the one mention first

Now lets write it in simplest form practically reducing it to its lowest term

\frac{96}{58}( we first write it as a fraction)

\frac{96}{58}÷\frac{2}{2}=48:29

So the answer is 48:29

HOPE IT HELPED

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. Could someone please explain this to me in detail. I am very confused. Thank you so much!. . A candle is 17 inches tall after
andrew-mc [135]

The generic equation of the line is:

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Substituting values we have:

m =\frac{15-17}{5-3}

Rewriting:

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