2 years ago

100 points. Please help. I'll give brainliest.

Mathematics

1 answer:

nata0808 [166]2 years ago

8 0

A: 95 people dislike both

B: 81

C: 21

You might be interested in

Can someone please help I can't solve this problem!!!!!!!!!!!

notsponge [240]

Answer:

8 dolls

Step-by-step explanation:

METHOD 1:

Step 1: Convert 25% into decimal (0.25)

Step 2: Multiply by 32 (32 × 0.25 = 8)

METHOD 2:

25% of a number will be one-fourth of that number. Divide 32 by 4 to get 8 (or multiply 32 by 1/4).

6 0

2 years ago

What number multiplied by itself 3 times equals-343

professor190 [17]

343*3=1029 this is the answer

7 0

2 years ago

Jason invests $1000 at a bank that offers 3% compounded annually. Write an equation to model the growth of the investment

MissTica

Y=1000*1.03^x is the correct compound recursive formula!

3 0

2 years ago

The sum of two numbers is x. if one of the numbers is 12, what is the other

nekit [7.7K]

Let y be the unknown number
$12+y=x \\ \\ y=x-12$

The other number is x - 12

3 0

2 years ago

I need help solving this problem. <img src="https://tex.z-dn.net/?f=4x%20cos%20%5E%7B-1%7D%20%282x%2B4%29-%20%5Csqrt%7B3-3%20x%5

Gnesinka [82]

Given:
$f(x)=4xcos^{-1}(2x+4)-\sqrt{3-3x^2}$

Using
$\frac{d}{dx}cos^{-1}(x)=-\frac{1}{\sqrt{1-x^2}}$
we derive
$\frac{d}{dx}4xcos^{-1}(2x+4)$
$=4cos^{-1}(2x+4)-\frac{8x}{\sqrt{1-(2x+4)^2}}$

Similarly, using
$\frac{d}{dx}\sqrt{x}=\frac{1}{2\sqrt{x}}$
we derive
$\frac{d}{dx}(-\sqrt{3-3x^2})$
$=\frac{3x}{\sqrt{3-3x^2}}$

Therefore, the derivative is
$f'(x)=\frac{d}{dx}(4xcos^{-1}(2x+4)-\sqrt{3-3x^2})$
$=4cos^{-1}(2x+4)-\frac{8x}{\sqrt{1-(2x+4)^2}}+\frac{3x}{\sqrt{3-3x^2}}$

3 0

2 years ago

Read 2 more answers