Mechanism with a small activation energy or one with large activation energy

Chemistry

1 answer:

tangare [24]3 years ago

8 0

Answer:

Rate depends on the rate constant. The rate constant depends on temperature and activation energy. If you have lower activation energy the rate will be higher. This is why catalysts are added since catalysts provide an alternate pathway that requires lower activation energy and catalysts are added to increase the rate of reaction.

Explanation:

This is only the answer if you were asking:

"Which corresponds to the faster rate: a mechanism with a small activation energy or one with a large activation energy?"

Thats what I understood about your question.

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hydrolysis of decapeptide P with the enzyme trypsin affords the following fragments: Glu-Gly-Lys, Gln-Val-Ile, Ala-Ser-Phe-Lys.

ehidna [41]

Answer:

The sequence of an amino acid P is:

Glu-Gly-Lys-Ala-Ser-Phe-Lys-Gln-Val-Ile

Explanation:

Fragments obtained on hydrolysis of decapeptide P by the action of an enzyme named trypsin:

Glu-Gly-Lys,
Gln-Val-Ile
Ala-Ser-Phe-Lys

Fragments obtained on hydrolysis of decapeptide P by the action of an enzyme named chymotrypsin:

Lys-Gln-Val-Ile,
Glu-Gly-Lys-Ala-Ser-Phe

In order to determine the sequence of protein P , we will arrange fragments in such a way so that common fragments or the common parts of fragments should come under each other.

On arranging these fragments :

Glu-Gly-Lys-Ala-Ser-Phe

Glu-Gly-Lys

Ala-Ser-Phe-Lys

Lys-Gln-Val-Ile

Gln-Val-Ile

The sequence of an amino acid P is:

Glu-Gly-Lys-Ala-Ser-Phe-Lys-Gln-Val-Ile

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9. You have a mini bottle of pure maple syrup. The full container has a mass of 137

cupoosta [38]

Answer:

Explanation:EDGE

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The atomic masses of 151eu and 153eu are 150.919860 and 152.921243 amu, respectively. The average atomic mass of europium is 151

vitfil [10]

Answer:- The natural abundance of $^1^5^1_E_u$ is 0.478 or 47.8% and $^1^5^3_E_u$ is 0.522 or 52.2% .

Solution:- Average atomic mass of an element is calculated from the atomic masses of it's isotopes and their abundances using the formula:

Average atomic mass = mass of first isotope(abundance) + mass of second isotope(abundance)

We have been given with atomic masses for $^1^5^1_E_u$ and $^1^5^3_E_u$ as 150.919860 and 152.921243 amu, respectively. Average atomic mass of Eu is 151.964 amu.

Sum of natural abundances of isotopes of an element is always 1. If we assume the abundance of $^1^5^1_E_u$ as n then the abundance of $^1^5^3_E_u$ would be 1-n .

Let's plug in the values in the formula:

$151.964=150.919860(n)+152.921243(1-n)$