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2 years ago

The internet is based on which three key technologies?.

Computers and Technology

1 answer:

BlackZzzverrR [31]2 years ago

8 0

Answer:

The Internet is based on which three key technologies? TCP/IP, HTML, and HTTP client/server computing, packet switching, and the development of communications standards for linking networks and computers TCP/IP, HTTP, and packet switching client/server computing, packet switching, and HTTP e-mail, instant messaging, and newsgroups

Explanation:

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____ data exist in a format that does not lend itself to processing that yields information.

Nastasia [14]

The word that goes in the blank is "unstructured."

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4 years ago

4. Write a program which selects two integer numbers randomly, adds the numbers and asks the user to enter the answer and then c

KIM [24]

Answer:

import random

number1 = random.randrange(0, 1000)

number2 = random.randrange(0, 1000)

answer = int(input("Enter a number: "))

if answer == number1 + number2:

print("Your answer is correct")

else:

print("Your answer is not correct")

Explanation:

The code is in Python

Create two integer numbers using random

Ask the user for an input

Check if answer is equal to number1 + number2. If they are equal, print "answer is correct". Otherwise, print "answer is not correct".

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3 years ago

In general, a presentation to kindergarteners should be less abstract than a presentation to corporate executives

Salsk061 [2.6K]

Make the presentation goofy so they will be more into it . your welcome

4 0

4 years ago

Read 2 more answers

Write a Comparator that compares String objects by the number of words they contain. Consider any nonwhitespace string of charac

Readme [11.4K]

Answer:

import java.util.Scanner;

public class num12 {

public static void main(String[] args) {

Scanner in = new Scanner(System.in);

System.out.println("Enter the first String");

String word1 = in.nextLine();

System.out.println("Enter the second String");

String word2 = in.nextLine();

System.out.println("Enter the third String");

String word3 = in.nextLine();

//Remove all white spaces

String cword1 = word1.replace(" ","");

String cword2 = word2.replace(" ","");

String cword3 = word3.replace(" ","");

//Comparing the string by their lengths

if(cword1.length()>cword2.length()&&cword1.length()>cword3.length()){

System.out.println(word1+" Is the longest");

}

else if(cword2.length()>cword1.length()&&cword2.length()>cword3.length()){

System.out.println(word2+" Is the longest");

}

else{

System.out.println(cword3+" Is the longest");

}

Explanation:

Using Java Programming Language

Use the Scanner Class to obtain the String values from the user

Save them in different variables

Use the replace() method in java to remove white space from any of the string entered

Using if and else statements compare the lengths of the strings (word.length()) returns the length of the word.

Print out the word that is longest

NOTE I have compared three Strings, comparing two would have been more straigth forward

8 0

4 years ago

Thirty percent of a magazine's subscribers are female. A random sample of 50 subscribers Answer the following questions using Ex

Ann [662]

Based on the mean of the subscribers, the sample size, and the standard deviation, the probability of females being at most 0.25 is 0.2202.

The probability that they are between 0.22 and 0.28 is 0.2703.

The probability that they are within 0.03 of the population proportion is 0.3566.

<h3>What is the probability that they are at most 0.25?</h3>

Using Excel, we shall assume that the distribution is normally distributed.

We can therefore use the NORM.DIST function:

=NORM.DIST(0.25,0.3,0.0648,TRUE)

= 0.2202

<h3 /><h3>What is the probability that they are between 0.22 and 0.28?</h3>

=NORM.DIST(0.28,0.3,0.0648,TRUE) - NORM.DIST(0.22,0.3,0.0648,TRUE)

= 0.2703

<h3>What is the probability that they are within 0.03 of the population proportion?</h3>

X high = 0.30 + 0.03

= 0.33

X low = 0.30 - 0.03

= 0.27

= NORM.DIST(0.33,0.3,0.0648,TRUE) - NORM.DIST(0.27,0.3,0.0648,TRUE)

= 0.3566.

Find out more on probability at brainly.com/question/1846009.

8 0

3 years ago