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FromTheMoon [43]

1 year ago

15

Ray buys a new tractor for $118,000. He receives consumer surplus of $13,000 on his purchase. Ray's willingness to pay is a. $11

8,000. b. $13,000. c. $131,000. d. $105,000.

1 answer:

baherus [9]1 year ago

4 0

$131,000
WTP-price paid

I hope this helps you
:)

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Motorcycle Manufacturers, Inc. projected sales of 59,700 machines for the year. The estimated January 1 inventory is 6,410 units

svlad2 [7]

Answer:

Production= 60,740

Explanation:

Giving the following information:

Sales= 59,700

Beginning inventory= 6,410

Desired Ending inventory= 7,450

<u>To calculate the production for the year, we need to use the following formula:</u>

Production= sales + desired ending inventory - beginning inventory

Production= 59,700 + 7,450 - 6,410

Production= 60,740

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A bond portfolio and a stock portfolio both provided an unrealized pretax return of 8% to a taxable investor. If the stocks paid

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Answer:

A bond portfolio and a stock portfolio both provided an unrealized pretax return of 8% to a taxable investor. If the stocks paid no dividends, we know that the ________.

The after-tax return of the stock portfolio was higher than the after-tax return of the bond portfolio.

Explanation:

The returns from the bond portfolio are taxed at the corporate rate while returns from stock investments are taxed at a lower rate. It is well-known that the risks from stock are higher than the risks from bonds. As a result, the stock investments always attract higher returns and less tax, as the investor can postpone the tax for a longer term. Again, stock investments can be for the long-term unlike bonds that have defined periods.

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3 years ago

What is the expected value when a $1 lottery ticket is bought in which the purchaser wins exactly $10 million if the ticket cont

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We expect to lose $0.37 per lottery ticket

<u>Explanation:</u>

six winning numbers from = { 1, 2, 3, ....., 50}

So, the probability of winning:

$P(win) = \frac{ no of favorable outcomes}{no of possible outcomes}$

$P(win) = \frac{1}{^5^0C_6} \\\\P (win) = \frac{6! X (50 - 6)!}{50!} \\\\P(win) = \frac{6! X 44!}{50!} \\\\P(win) = \frac{1}{15,890,700}$

The probability of losing would be:

P(loss) = 1 - P(win)

$P(loss) = 1 - \frac{1}{15,890,700} \\\\P(loss) = \frac{15,890,699}{15,890,700}$

According to the question,

When we win, then we gain $10 million and lose the cost of the lottery ticket.

So,

$10,000,000 - 1 = $9,999,999

When we lose, then we lose the cost of the lottery ticket = $1

The expected value is the sum of the product of each possibility x with its probability P(x):

E(x) = ∑ xP(x)

$= 9,999,999 X \frac{1}{15,890,700} + ( -1 ) X \frac{15,890,699}{15,890,700} \\\\=- \frac{5,890,700}{15,890,700} \\\\= - \frac{58,907}{158,907} \\\\= - 0.37$

Thus, we expect to lose $0.37 per lottery ticket

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