Answer:
A. The work done during the process is W = 0
B. The value of heat transfer during the process Q = 442.83 
Explanation:
Given Data
Initial pressure  = 100 k pa
 = 100 k pa
Initial temperature  = 25 degree Celsius = 298 Kelvin
 = 25 degree Celsius = 298 Kelvin
Final pressure  = 300 k pa
 = 300 k pa
Vessel is rigid so change in volume of the gas is zero. so that initial volume is equal to final volume.
⇒  =
 =  ------------- (1)
 ------------- (1)
Since volume of the gas is constant so pressure of the gas is directly proportional to the temperature of the gas.
⇒ P ∝ T
⇒  =
 = 
⇒ Put all the values in the above formula we get the final temperature 
⇒  =
 =  × 298
 × 298
⇒  = 894 Kelvin
 = 894 Kelvin
(A). Work done during the process is given by W = P × ( )
)
From equation (1),   =
 =  so work done W = P × 0 = 0
 so work done W = P × 0 = 0
⇒ W = 0
Therefore the work done during the process is zero.
Heat transfer during the process is given by the formula Q = m  (
 (  -
 - )
 )
Where m = mass of the gas = 1 kg
 = specific heat at constant volume of nitrogen = 0.743
 = specific heat at constant volume of nitrogen = 0.743 
Thus the heat transfer Q = 1 × 0.743 × ( 894- 298 )
⇒ Q = 442.83 
Therefore the value of heat transfer during the process Q = 442.83 