A higher frequency. I just got this answer on usa test prep.
Distance = speed / time
speed = 95 m/s
time = 3 s
distance = 95 / 3 m
displacement = 95/3 m or 32 m (2 s.f.)
The velcocity equals acceleration times time
which is 50 ms per sec
Answer:
0.39
Explanation:
In order not to slide, you must have exactly the same acceleration of the train:

where
g = 9.81 m/s^2
There is only one force acting on you: the static frictional force that "pulls" you forward, and it is given by

According to Newton's second law, the net force acting on you (so, the frictional force) must be equal to your mass times the acceleration, so we have

from which we find

so, the minimum coefficient of static friction must be 0.39.
Answer:
the final velocity of the object is 53.04 m/s.
Explanation:
Given;
initial velocity of the projectile, u = 50 m/s
displacement of the object, d = 16 m
let the final velocity of the object = v
Apply the following kinematic equation to determine the final velocity of the projectile.
v² = u² + 2gd
v² = 50² + (2 x 9.8 x 16)
v² = 2813.6
v = √2813.6
v = 53.04 m/s
Therefore, the final velocity of the object is 53.04 m/s.