Answer:
The width of billboard is "[x]" and the height of billboard is "[y"]. If total area of billboard is
then
Step-by-step explanation:
• The total width of billboard is [x]. Therefore the width of printed area will be (x-10) by excluding margin of left and right side.
• The total height of billboard is [y]. Therefore the height of printed area will be [(y-6)] by excluding the margin of top and bottom from the total height.
• To find the printed area of billboard calculations are given below:


On taking the first order derivative of A
![\[A'=-6+\left( \frac{90000}{{{x}^{2}}} \right)\]](https://tex.z-dn.net/?f=%5C%5BA%27%3D-6%2B%5Cleft%28%20%5Cfrac%7B90000%7D%7B%7B%7Bx%7D%5E%7B2%7D%7D%7D%20%5Cright%29%5C%5D)

• Hence
and ![\[y=\frac{900}{\sqrt{150}}\]](https://tex.z-dn.net/?f=%5C%5By%3D%5Cfrac%7B900%7D%7B%5Csqrt%7B150%7D%7D%5C%5D)
Learn More about Differentiation Here:
brainly.com/question/13012860
Answer:
[/tex]
Step-by-step explanation:
The generating function of a sequence is the power series whose coefficients are the elements of the sequence. For the sequence

the generating function would be

we can multiply P(x) by x to get
Note that

which for
can be rewritten as

Answer:
15 minutes
Step-by-step explanation:
First, the motorcycle goes at a speed of 40 km/hr.
The question asks for how long it would take to travel 10 km.
Well, there are 60 minutes in an hour, since we will be translating into minutes.
Also, 10 km is 1/4 of 40 km, so it would make sense that the time length would be 1/4 of an hour as well.
1/4 of 60 minutes is 15 minutes. So it takes 15 minutes for the motorcycle to travel 10 km.
Now, if all this wordy stuff is too much to comprehend, you can also solve using proportional relationships.

Now cross multiply:

Divide both sides by 40:

Again, this shows that it wouls take 15 minutes for the motorcycle to travel 10 km.
This is hard to understand , do u have a photo
A=$20.20/10gal=$2.02 per gal
B=$26.04/12gal=$2.17 per gal
C=$28.14/14gal=$2.01 per gal
D=$30.45/15gal=$2.03 per gal
So C is the cheapest per gallon.