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vitfil [10]
2 years ago
10

What is the law of conservation energy?

Chemistry
2 answers:
sattari [20]2 years ago
5 0

Answer: The law of conservation of energy is a physical law that states energy cannot be created or destroyed but may be changed from one form to another. Another way of stating this law of chemistry is to say the total energy of an isolated system remains constant or is conserved within a given frame of reference.

Sedbober [7]2 years ago
4 0

Answer:

The law of conservation of energy states that energy can neither be created nor destroyed - only converted from one form of energy to another. This means that a system always has the same amount of energy unless it's added from the outside.

Explanation:

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Write and label the density triangle
Slav-nsk [51]

Answer:

It is basically a way of telling you how to solve for different variables in the equation d=m/v

Explanation:

8 0
3 years ago
What are some compounds that are made from the element copper?
PSYCHO15rus [73]

Answer:

All of these compounds are made from the element copper. Copper Acetates, Cuprous Oxide, Cupric Oxide (otherwise know as black copper oxide), Cupric Chloride, Copper Oxychloride, Cuprous Chloride, Cupric Nitrate, Copper Cyanide.

Explanation:

Copper is considered an element. You can use copper for Jewelry, Table Tops, Sinks, Dark Chocolate, Leafy Greens, Lobster, Nuts and Seeds, Mushrooms, Oysters, Liver and etc other nutrience. Copper is an easily molded base metal that is often added to precious metals to improve their elasticity, flexibility, hardness, colour, and resistance to corrosion.

6 0
2 years ago
Is diphenylamine a solid, liquid, or a gas at room temperature
goblinko [34]

Answer:

Solid

Explanation:

Diphenylamine has a melting point of 127.4 F or 53 C so at room temperature ~70 F or 21 C its a solid.

3 0
3 years ago
A buffer solution contains 0.479 M NaHCO3 and 0.342 M Na2CO3. Determine the pH change when 0.091 mol HNO3 is added to 1.00 L of
pshichka [43]

Answer:

ΔpH = 0.20

Explanation:

The buffer of HCO₃⁻ + CO₃²⁻ has a pka of 10.2

HCO₃⁻ ⇄ H⁺ + CO₃²⁻

There are 0.479moles of NaHCO₃ and 0.342moles of Na₂CO₃.

Using Henderson-Hasselbalch formula:

pH = pka + log [Base] / [Acid]

pH = 10.2 + log 0.342mol / 0.479mol

<em>pH = 10.05</em>

NaOH reacts with HCO₃⁻ producing CO₃²⁻, thus:

NaOH + HCO₃⁻ → CO₃²⁻ + H₂O + Na⁺

0.091 moles of NaOH produce the same moles of CO₃²⁻ and consume HCO₃⁻. Moles of these species are:

CO₃²⁻: 0.342mol + 0.091mol: 0.433mol

HCO₃⁻: 0.479mol - 0.091 mol: 0.388mol

Using Henderson-Hasselbalch formula:

pH = pka + log [Base] / [Acid]

pH = 10.2 + log 0.433mol / 0.388mol

pH = 10.25

That means change of pH, ΔpH is:

ΔpH = 10.25 - 10.05 = <em>0.20</em>

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I hope it helps!

3 0
3 years ago
Ethyl butyrate, ch3ch2ch2co2ch2ch3, is an artificial fruit flavor commonly used in the food industry for such flavors as orange
kakasveta [241]

Answer:

             14.15 g of Ethyl Butyrate

Solution:

The Balance Chemical Equation is as follow;

           Butanoic Acid  +  Ethanol    →    Ethyl Butyrate  +  Water

Molar Mass of Butanoic Acid  =  88.11 g.mol⁻¹

Molar Mass of Ethanol  =  46.07 g.mol⁻¹

Molar Mass of Ethyl Butyrate  =  116.16 g.mol⁻¹

Molar Mass of Water  =  18.01 g.mol⁻¹

Step 1: Calculating Theoretical Yield:

According to Equation,

           88.11 g (1 mol) Butanoic Acid forms  =  116.16 g (1 mol) Ethyl Butyrate

So,

                 13.58 g Butanoic Acid will form  =  X g of Ethyl Butyrate

Solving for X,

                     X  =  (13.58 g × 116.16 g) ÷ 88.11 g

                     X  =  17.90 g

                     Theoretical Yield  =  17.90 g

Step 2: Calculating Actual Yield:

As,

                     %age Yield  =  Actual Yield ÷ Theoretical Yield × 100

Solving for Actual Yield,

                      Actual Yield  =  %age Yield × Theoretical Yield ÷ 100

Putting Values,

                      Actual Yield  =  79.1 × 17.90 ÷ 100

                      Actual Yield =  14.15 g of Ethyl Butyrate

6 0
3 years ago
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