Answer:
The volume of the balloon will be 5.11L
Explanation:
An excersise to solve with the Ideal Gases Law
First of all, let's convert the pressure in mmHg to atm
1 atm = 760 mmHg
760 mmHg ___ 1 atm
755.4 mmHg ____ (755.4 / 760) = 0.993 atm
922.3 mmHg ____ ( 922.3 / 760) = 1.214 atm
T° in K = 273 + °C
28.5 °C +273 = 301.5K
26.35°C + 273= 299.35K
P . V = n . R .T
First situation: 0.993atm . 6.25L = n . 0.082 . 301.5K
(0.993atm . 6.25L) / 0.082 . 301.5 = n
0.251 moles = n
Second situation:
1.214 atm . V = 0.251 moles . 0.082 . 301.5K
V = (0.251 moles . 0.082 . 301.5K) / 1.214 atm
V = 5.11L
Answer:
The answer is "23765.4"
Explanation:
Motor weight average number 
Poly condensation degree dependent on the average number of molecular weights is as follows:
All monomer module, in this case, is propylene
Sunrise. Unit Wt = Mol. Propylene weight
13.48 is your answer.
M=moles/liters we have M=.115 and moles=1.55
Input those values into the equation
.115=1.55/L
Solve for L
1.55/.115=13.48
<h3>
Answer:</h3>
300 kPa
<h3>
Explanation:</h3>
Concept tested: Gas Laws (Combined gas law)
Initial pressure, P₁ = 100 kPa
Initial temperature,T₁ = 27°C
But, K = °C + 273, therefore, T₁ = 300 K
Initial volume, V₁ = 900 L
New temperature, T₂ = -73°C
= -73°C + 273
= 200 K
New volume, V₂ = 200 L
We are required to calculate the new pressure, P₂
- To find the new pressure of the gas, we are going to use the combined gas law;
- Combined gas law combines both Charles's law and Boyle's law.
- According to the combined gas law;
P₁V₁/T₁ = P₂V₂/T₂
- To calculate the new Pressure, P₂, we rearranging the formula;
P₂ =(P₁V₁T₂) ÷ (V₂T₁)
Therefore;
P₂ = (100 kPa × 900 L × 200 K) ÷ (200 L × 300 K)
= 300 kPa
Therefore, a pressure of 300 kPa must be applied.
