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2 years ago

What is the surface area of this rectangular box?

Physics

1 answer:

san4es73 [151]2 years ago

3 0

Answer:

where is the box? ehh bring the box out

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The city bus traveled 30 miles in 30 minutes. What was its speed in mph?

jonny [76]

The answer will be B.60mph

4 0

3 years ago

Read 2 more answers

An irrigation canal has a rectangular cross section. At one point whare the canal is 16.0 m wide, and the water is 3.8 m deep, t

Irina-Kira [14]

Answer:

The depth of the water at this point is 0.938 m.

Explanation:

Given that,

At one point

Wide= 16.0 m

Deep = 3.8 m

Water flow = 2.8 cm/s

At a second point downstream

Width of canal = 16.5 m

Water flow = 11.0 cm/s

We need to calculate the depth

Using Bernoulli theorem

$A_{1}V_{1}=A_{2}V_{2}$

Put the value into the formula

$16.0\times3.8\times2.8=16.5\times x\times 11.0$

$x=\dfrac{16.0\times3.8\times2.8}{16.5\times11.0}$

$x=0.938\ m$

Hence, The depth of the water at this point is 0.938 m.

7 0

3 years ago

Taste and smell are called chemical senses because:

Bingel [31]

Answer:

The answer is a," their receptors are sensitive to chemical molecules."

3 0

3 years ago

A beam of light passes through a liquid into air. Angle 1, angle of

Ede4ka [16]

Answer: 1.57

Explanation:

This described situation is known as Refraction, a phenomenon in which light bends or changes its direction when passing through a medium with a index of refraction different from the other medium.

In this context, the index of refraction is a number that describes how fast light propagates through a medium or material.

According to Snell’s Law:

$n_{1}sin(\theta_{1})=n_{2}sin(\theta_{2})$ (1)

Where:

$n_{1}$ is the first medium index of refraction (the value we want to know)

$n_{2}=1$ is the second medium index of refraction (air)

$\theta_{1}=23\°$ is the angle of incidence

$\theta_{2}=38\°$ is the angle of refraction

Now, let's find $n_{1}$ from (1):

$n_{1}=n_{2}\frac{sin \theta_{2}}{sin \theta_{1}}$ (2)

Substituting the known values:

$n_{1}=1\frac{sin(38\°)}{sin(23\°)}$

Finally:

$n_{1}=1.57$

3 0

3 years ago

A car is moving with a uniform speed of 15.0 m/s along a straight path. What is the distance covered by the car in 12.0 minutes?

vladimir1956 [14]

12.0 min = 720. s

so the distance covered moving at a constant 15.0 m/s is

(15.0 m/s) (720. s) = 10,800 m = 10.8 km = 1.08 × 10¹ km

6 0

2 years ago