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Vikentia [17]
3 years ago
10

Consider a roller coaster begins 15m above the ground. If the cart has a mass of 75kg, what is the velocity of the cart halfway

to the ground?
Physics
1 answer:
SashulF [63]3 years ago
7 0

Answer:

v = 12.12 m/s

Explanation:

Given that,

The mass of the cart, m = 75 kg

The roller coaster begins 15 m above the ground.

We need to find the velocity of the cart halfway to the ground. Let the velocity be v. Using the conservation of energy at this position, h = 15/2 = 7.5 m

mgh=\dfrac{1}{2}mv^2\\\\v=\sqrt{2gh} \\\\v=\sqrt{2\times 9.8\times 7.5} \\\\v=12.12\ m/s

So, the velocity of the cart is 12.12 m/s.

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A balloon is filled with a gas at 111 kPa when the temperature was 22*C. If the temperature
storchak [24]

119.7kPa

Explanation:

Given parameters:

Pressure of gas in balloon = 111kPa

Temperature of gas = 22°C

Final temperature = 45°C

Unknown:

Final pressure = ?

Solution:

Since the gases in the balloon have the same number of moles. We can apply a derivative of the combined gas law to solve this problem.

At constant volume the pressure of a given mass of gas varies directly with the absolute temperature.

           \frac{P1}{T1}   =  \frac{P2}{T2}

P1 is the initial pressure

P2 is the final pressure

T1 is the initial temperature

T2 is the final temperature

 convert from celcius to kelvin:

       tK = 273 + tC

   T1 = 273 + 22 = 295K

   T2 = 273 + 45 = 318K

      \frac{111}{295}  =  \frac{P2}{318}

  P2 = 119.7kPa

learn more:

Ideal gas brainly.com/question/13064292

#learnwithBrainly

3 0
3 years ago
What are limits that would be age appropriate for teens vs toddlers? give me some examples of limits that you may have for a tee
Pavlova-9 [17]

The limits which would be age appropriate for toddlers include being flexible and realistic while that of a teen should be more rigid.

<h3>Who are Toddlers?</h3>

This refers to a child whose age ranges from 1 year to 4 years and limits set for them should be flexible due to it helping them feel more secure and decreases anxiety.

Example of limits that you may have for a teen is reducing their screen time while an example of limits for toddlers is correcting their junk eating habits. Teens should have a rigid limit so as to enable them do the right things at all times due to their strong emotions.

Read more about Limits here brainly.com/question/1419949

#SPJ1

6 0
2 years ago
The electric output of a power plant is 716 MW. Cooling water is the main way heat from the powerplant is rejected, and it flows
Stels [109]

Answer:

(a) 83475 MW

(b) 85.8 %

Explanation:

Output power = 716 MW = 716 x 10^6 W

Amount of water flows, V = 1.35 x 10^8 L = 1.35 x 10^8 x 10^-3 m^3

mass of water, m = Volume  x density = 1.35 x 10^8 x 10^-3 x 1000

                                                               = 1.35 x 10^8 kg

Time, t = 1 hr = 3600 second

T1 = 25.4° C, T2 = 30.7° C

Specific heat of water, c = 4200 J/kg°C

(a) Total energy, Q = m x c x ΔT

Q = 1.35 x 10^8 x 4200 x (30.7 - 25.4) = 3 x 10^12 J

Power = Energy / time

Power input = P = \frac{3 \times 10^{12}}{3600}=8.35 \times 10^{8}W

Power input = 83475 MW

(b) The efficiency of the plant is defined as the ratio of output power to the input power.

\eta =\frac{Power output}{Power input}

\eta =\frac{716}{83475}=0.858

Thus, the efficiency is 85.8 %.

7 0
3 years ago
A coffee mixture has beans that sell for $0.72 a pound and beans that sell for $0.52. If 110 pounds of beans create a mixture wo
Burka [1]
X is a weight of the beans that sells for $0.72 apound
y is a weight of the beans that sells for $0.52 a pound
{x+y=110
{0.72x+0.52y=110*0.74

x=110-y
0.72*(110-y)+0.52y=81.4
79.2-0.72y+0.52y=81.4
-0.2y=2.2

Just use 110 pounds of beans that cost $0.52 and your revenue will be 
30 percents
Or use 110 pounds of beans that cost $0.72 and your revenue will be
2.7 percents
7 0
4 years ago
Now it's your turn
eduard

Answer:

The average force the golf club exerts on the ball is 600 N

Explanation:

Newton's second law of motion states that force, F, is directly proportional to the rate of change of momentum produced

F = m× (v₂ - v₁)/(Δt)

The given parameters of the motion of the ball are;

The mass of the ball, m = 45 g = 0.045 kg

The initial velocity of the ball, v₁ = 0 m/s

The speed with which the ball was hit by the golfer, v₂ = 40 m/s

The duration of contact between the golf club and the ball, Δt = 3 ms = 0.003 seconds (s)

By Newton's law of motion, the average force, 'F', which the golf club exerts on the ball is therefore, given as follows;

F = 0.045 kg × (40 m/s - 0 m/s)/(0.003 s) = 600 N

The average force the golf club exerts on the ball = F = 600 N.

5 0
3 years ago
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