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3 years ago

MATCH THESE ^-^ Match Newton's law with the correct statement.

Physics

2 answers:

ikadub [295]3 years ago

4 0

1 and A
2 and B
3 and D
4 and C

Lilit [14]3 years ago

3 0

Answer:

1. law of universal gravitation -"The box of cotton is much easier to lift than the box of books."

2. 1st law of motion (law of inertia) - "My coffee spilled all over because you slammed on your brakes!"

3. 2nd law of motion - "I can't hit the ball farther than you because you're stronger than I am."

4. 3rd law of motion - "That bat hurt my hands when I hit the ball!"

Explanation:

Law of gravitation states that there exists an attractive force between two objects having mass. The magnitude of the force depends upon the masses of the two objects and inversely proportional to the distance between them. Thus, greater the mass, greater would be the force. weight of an object is determines the gravitation pull of the Earth on the mass of the object. Thus, it is easier to lift a box of cotton which is lighter in weight than a box of books.

Newton's first law states that an object remains in state of rest or motion unless exerted by an unbalanced external force. Thus, when you are sitting in the car and the driver applies break suddenly, you experience a pull force because you continue to move forward while the car suddenly decelerates and if you would be holding coffee, it can spill.

Second law of motion states that force is rate of change of momentum. Momentum depends on the mass and velocity of the object. Greater the mass, greater would be momentum. Thus, A person who is stronger would be able to hit the ball harder and hence faster than the other.

Third law of motion states that, for every action, there is equal and opposite reaction. Thus, when when you a ball with the bat, you are applying force with your hands. Hence, your hands would also experience an equal amount of force in the opposite direction and you would get hurt.

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Problem 7:__deletededc326999bef85931fda5d1ab0d68e21218f27b46f4f11ab80872358251b584ddeleted__ 0N86-C1-52-40-A837-22820 If object

laila [671]

Answer:

the kinetic energy of body B is twice the kinetic energy of body A

Explanation:

The kinetic energy of a body is given by

K = ½ m v²

If two objects leave the same point, suppose that at the same height when they reach the ground they have the same velocity.

Therefore if the mass of body b is twice the mass of body A

$m_{b} = 2 m_{a}$

$K_{b}$ = ½ (2 $m_{a}$ ) v²

K_{b} = 2 (½ m_{a} v²)

K_{b} = 2 K_{a}

therefore the kinetic energy of body B is twice the kinetic energy of body A

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3 years ago

A bromine atom has an atomic number of 35 and an atomic mass of 80. What is the structure of this atom?

Brums [2.3K]

Answer:

D. It has a central nucleus composed of 35 protons and 45 neutrons,

surrounded by an electron cloud containing 35 electrons.

hope this was helpful ! <3

3 0

2 years ago

Read 2 more answers

What are the two forces involved in an interaction called

natka813 [3]

Answer:These two forces are called action and reaction forces and are the subject of Newton's third law of motion. Formally stated, Newton's third law is: For every action, there is an equal and opposite reaction. The statement means that in every interaction, there is a pair of forces acting on the two interacting objects.

Explanation:

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3 years ago

A piece of metal has a mass of 10g and a mass of 2cm

qwelly [4]

Answer:

so whats the questain?!

Explanation:

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3 years ago

A box is placed on a conveyor belt that moves with a constant speed of 1.05 m/s. The coefficient of kinetic friction between the

sveticcg [70]

Answer:

The box stops in 0.139 seconds, after moving 7.29cm (0.0729m) backwards relative to the belt.

Explanation:

As the box is initially at rest relative to the earth, it is moving backwards with a speed of 1.05m/s relative to the belt. Then, the frictional force acts on the box to make it stop relative to the belt. So, we first have to write the equations of motion of the box in each axis:

$x: f_k=ma\implies a=\frac{f_k}{m} \\\\y: N-mg=0\implies N=mg$

Since the frictional force $f_k$ is equal to $f_k=\mu_k N=\mu_k mg$ , then we have that the acceleration is:

$a=\frac{\mu_k mg}{m}=\mu_k g$

Now, from the definition of acceleration we get:

$a=\frac{v-v_0}{t}\implies t=\frac{v-v_0}{a}$

And, as the final velocity is zero because the box gets to a stop, we have:

$t=-\frac{v_0}{a}=-\frac{v_0}{\mu_k g}$

(Don't worry about the negative sign. It will disappear because the initial velocity is also negative, since we take the box initially moving backwards)

Then, plugging in the given values, we calculate the time:

$t=-\frac{(-1.05m/s)}{0.770(9.81m/s^{2})}=0.139s$

In words, the time the box takes to stop sliding relative to the belt is 0.139s.

The displacement of the box in this time, is given by the kinematics formula:

$v^{2}=v_0^{2}+2ax\implies x=-\frac{v_0^{2}}{2\mu_kg}$

Finally, we calculate the displacement:

$x=-\frac{(1.05m/s)^{2} }{2(0.770)(9.81m/s^2)}=-0.0729m=-7.29cm$

This means that the box moves 7.29cm backwards relative to the belt.

4 0

3 years ago