1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
maks197457 [2]
3 years ago
10

Hydrogen is the second most abundant gas in the atmosphere? True or false?

Physics
1 answer:
Alenkinab [10]3 years ago
7 0
False as oxygen is the second most abundant and nitrogen is the most abundant at 78%.
You might be interested in
What does the ideal gas law allow a scientist to calculate that the other laws do not?
Daniel [21]
The ideal gas law.
PV=nRT
P=presure
V=volume
n=number of moles
R=Gas costant
T=temperature.

Answer: a. Number of moles.
6 0
3 years ago
Read 2 more answers
A material that transmits nearly all the light in a ray because it offers little resistance to the light is ________.
Nina [5.8K]

Answer:

D. transparent.

Explanation:

A material that transmits nearly all the light in a ray because it offers little resistance to the light is <u>transparent.</u>

A transparent material allows light to pass through them with little or no resistance enabling them see-through. A material that transmits nearly all the light rays that pass through it because it offers little resistance to the light is TRANSPARENT. Examples of transparent materials are water,  glass (flint and crown), air, and diamond.

4 0
3 years ago
Determine the angle of an incline that would yield a constant velocity, given the coefficient of kinetic friction is 0.10.
azamat

Answer:

\theta=5.71^{o}

Explanation:

In order to solve this problem, we mus start by drawing a free body diagram of the given situation (See attached picture).

From the free body diagram we can now do a sum of forces in the x and y direction. Let's start with the y-direction:

\sum F_{y}=0

-W_{y}+N=0

N=W_{y}

so:

N=mgcos(\theta)

now we can go ahead and do a sum of forces in the x-direction:

\sum F_{x}=0

the sum of forces in x is 0 because it's moving at a constant speed.

-f+W_{x}=0

-\mu_{k}N+mg sen(\theta)=0

-\mu_{k}mg cos(\theta)+mg sen(\theta)=0

so now we solve for theta. We can start by factoring mg so we get:

mg(-\mu_{k} cos(\theta)+sen(\theta))=0

we can divide both sides into mg so we get:

-\mu_{k} cos(\theta)+sen(\theta)=0

this tells us that the problem is independent of the mass of the object.

\mu_{k} cos(\theta)=sen(\theta)

we now divide both sides of the equation into cos(\theta) so we get:

\mu_{k}=\frac{sen(\theta)}{cos(\theta)}

\mu_{k}=tan(\theta)

so we now take the inverse function of tan to get:

\theta=tan^{-1}(\mu_{k})

so now we can find our angle:

\theta=tan^{-1}(0.10)

so

\theta=5.71^{o}

8 0
3 years ago
Một chất điểm DĐĐH có phương trình x=Acos(omega t). Tìm thời gian chất điểm qua vtcb theo chiều dương lần thứ 2?
Arada [10]

Answer:

yyeyrhdhshysyeuhdjxnxmzmakalwooeitjtjdjjs

8 0
3 years ago
Two disks of polaroid are aligned so that they polarize light in the same plane. Calculate the angle through which one sheet nee
Olegator [25]

Answer: The unpolarized light's intensity is reduced by the factor of two when it passes through the polaroid and becomes linearly polarized in the plane of the Polaroid. When the polarized light passes through the polaroid with the plane of polarization at an angle \theta with respect to the polarization plane of the incoming light, the light's intensity is reduced by the factor of \cos^2\theta (this is the Law of Malus).

Explanation: Let us say we have a beam of unpolarized light of intensity I_0 that passes through two parallel Polaroid discs with the angle of \theta between their planes of polarization. We are asked to find \theta such that the intensity of the outgoing beam is I_2. To solve this we follow the steps below:

Step 1. It is known that when the unpolarized light passes through a polaroid its intensity is reduced by the factor of two, meaning that the intensity of the beam passing through the first polaroid is

I_1=\frac{I_0}{2}.

This beam also becomes polarized in the plane of the first polaroid.

Step 2. Now the polarized beam hits the surface of the second polaroid whose polarization plane is at an angle \theta with respect to the plane of the polarization of the beam. After passing through the polaroid, the beam remains polarized but in the plane of the second polaroid and its intensity is reduced, according to the Law of Malus, by the factor of \cos^2\theta. This yields I_2=I_1\cos^2\theta. Substituting from the previous step we get

I_2=\frac{I_0}{2}\cos^2\theta

yielding

\frac{2I_2}{I_0}=\cos^2\theta

and finally,

\theta=\arccos\sqrt{\frac{2I_2}{I_0}}

3 0
3 years ago
Other questions:
  • Two Velocities in a Traveling Wave? Wave motion is characterized by two velocities: the velocity with which the wave moves in th
    14·1 answer
  • Assume that the moon is hit by about 25 million micrometeorite impacts each day, and that these impacts strike randomly around t
    10·2 answers
  • A hot air ballo0n is ascending straight up at a constant
    15·1 answer
  • According to Newton´s second law of motion, what does an object with more mass require? Question 8 options:
    12·2 answers
  • A man jumps off a building that is 40 stories tall and 160 meters high
    13·1 answer
  • What provides the centripetal force needed to keep Earth in orbit?
    12·2 answers
  • A student conducted an experiment to measure the acceleration due to gravity 'g' of a simple pendulum.
    8·1 answer
  • What happens to a bar of metal when its heated?
    13·2 answers
  • PLS HELP DUE TODAY
    14·1 answer
  • Which force is sometimes attractive and has an infinite range?
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!