Answer:
Dy/Dx=x
(
2
ln
(
x
)
−
1
)/
ln
^2
(
x)
Step-by-step explanation:
We have this function and let's derive it in terms of x.
y =x^2/In x
Dy/Dx=(x^2/In x)'=2/lnx *(x^2)'-(x^2/In x)'=> 2
x
*ln
(
x
)
−
x
*ln
^2
(
x
)
=x
(
2
ln
(
x
)
−
1
)/
ln
^2
(
x)
Answer:
<em>suwi6q74diyer7ityw7reuDjuss36audlsgo74wridoyaurslhjsgjfaufalakateUd</em>
Step-by-step explanation:
will3urafg-"7'-"/-()4<u> </u><u>mhl374</u><u>y</u><u>3</u><u>l</u><u>u</u><u>s</u><u>d</u><u>u</u><u>s</u><u>i</u><u>t</u><u>z</u><u>l</u><u>a</u><u>7</u><u>w</u><u>h</u><u>f</u><u>z</u><u>s</u><u>p</u><u>r</u><u>X</u><u>j</u><u>a</u><u>u</u><u>e</u><u>g</u><u>k</u><u>z</u><u>h</u><u>r</u><u>o</u><u>y</u>
Step-by-step explanation:
always draw triangle b first. for triangle b it is reflected across the x-axis which means all y valies become negative. then for triangle c, you swap the x and y values around.
Remark
I'm going to interpret this equation as
D = ut + kt² The only difference is the 2.
Solution
Subtract kt² from both sides.
D - kt² = ut Now divide by u on both sides.

The t's cancel out. on the right. You are left with u on the right.

Answer:
Step-by-step explanation:
You draw a line right down the middle so it makes it to equal triangle