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kirill [66]
2 years ago
8

What is the measure of 21? 100° 90° 80° 85° 95%​

Mathematics
1 answer:
Scorpion4ik [409]2 years ago
8 0

Answer:

A quadrilateral's interior angles have a sum of 360°.

Given that we have 85°, 100°, and 90°(the right angle), and an unknown angle.

We can add these angles plus the unknown angle to equal a total of 360°.

85 + 100 + 90 + x(our unknown missing angle) = 360

simplify

275 + x = 360

Isolate x by subtract 275 from both sides;

-275       -275

x = 85, ∠1 = 85°

We can also double check:-

85 + 100 + 90 + <u>85</u> = 360

360 = 360 which is correct.

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3 years ago
Classify ABC by its sides. Then determine whether it is a right triangle.
m_a_m_a [10]

Answer:

∴Given Δ ABC is not a right-angle triangle

a= AB = √45 = 3√5

b = BC = 12

c = AC = √45 = 3√5

Step-by-step explanation:

Given vertices are A(3,3) and B(6,9)

            AB = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2}  }

            AB = \sqrt{(9-3)^{2}+(6-3)^{2}  } = \sqrt{6^{2}+3^{2}  } =\sqrt{45}

Given vertices are  B(6,9) and C( 6,-3)

       B C = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2}  }

             =  \sqrt{(-3-9)^{2}+(6-6)^{2}  } =\sqrt{12^{2} } = 12

    BC = 12

Given vertices are  A(3,3) and C( 6,-3)

 AC = \sqrt{(6-3)^{2}+(-3-3)^{2}  } = \sqrt{9+36} = \sqrt{45}

AC² = AB²+BC²

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5 0
3 years ago
(29) A runner is running 10 miles per hour.
leva [86]

The conversions factors needed are 1 mile= 5280 feet and 1 hour = 3600 seconds, speed in ft/s = 14.67 ft/s  

<u>Solution: </u>

Given, A runner is running 10 miles per hour.  

We have to find what conversion factors should be used to convert 10 mi/hr to ft/s?

Now, speed of runner = 10 miles per hour.

But we need the units to be in ft / s.

Then, conversion factors are miles to feet and hours to seconds.

Now, miles to feet ⇒ 1 mile = 5280 feet.

Now, hours to seconds ⇒ 1 hour = 3600 seconds

\begin{array}{l}{\text { So,speed }=10 \frac{\text { miles }}{\text { hour }}} \\\\ {\text { speed }=10 \times \frac{1 \text { miles }}{1 \text { hour }}} \\\\ {\text { Speed }=10 \times \frac{5280 \text { feet }}{3600 \text { seconds }}} \\\\ {\text { Speed }=\frac{52800}{3600}=14.67 \mathrm{ft} / \mathrm{s}}\end{array}

Hence, the conversions needed are 1 mile = 5280 feet and 1 hour = 3600 seconds, speed in ft/s = 14.67 ft/s

6 0
3 years ago
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