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sveticcg [70]
2 years ago
12

Work out the area of the parallelogram

Mathematics
1 answer:
11Alexandr11 [23.1K]2 years ago
8 0

Answer:

b x h

Step-by-step explanation:

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Graph the image of the given triangle under a dilation with a scale factor of 1/4 and center of dilation ​(0, 0)
schepotkina [342]

Answer:

The image in the attached figure

Step-by-step explanation:

we know that

The dimensions of the image of the given triangle are equal to the original dimensions of the pre-image multiplied by the scale factor

In this problem the scale factor is 1/4

The height of the pre-image is 4 units

The base of the pre-image is 8 units

Find out the dimensions of the image

The height of the image is (4)\frac{1}{4}=1\ unit

The base of the image is (8)\frac{1}{4}=2\ units

The image in the attached figure

6 0
3 years ago
Use the scale of 1cm=45 km
alex41 [277]

Answer:

d = 7.4 cm is the distance between the two cities on the map.

Step-by-step explanation:

Let d = the distance measured on the map in centimeters (cm) between any two locations and let D be the actual distance in kilometers (km) between these same two locations.

Since the scale on the map is 1 cm = 45 km, then the ratio of the distance on the map to the actual distance is equal to 1cm/45 km; therefore the quotient of any measured distance d on the map divided by the corresponding much longer actual distance D would have to maintain (equal) this same ratio; In other words, we can set up the following proportion to solve for d given the actual distance D = 333 km as follows:

1 cm/45 km = d/D

Substituting, we get:

1 cm/45 km = d/333 km

d/333 km = 1 cm/45 km

(d/333 km)(333 km) = (1 cm/45 km)(333 km)

d = (333 km/45 km)(1 cm)

d = 7.4 cm is the distance between the two cities on the map.

Check:

1 cm/45 cm = d/333 km

1 cm/45 cm = 7.4 cm/333 km

1 cm/45 cm = 1 cm/45 km (Therefore, the distance ratio of the map has been maintained

3 0
1 year ago
Explain the distance formula. Then use it to calculate the
Alex777 [14]

Answer:

dAB=10\ units

Step-by-step explanation:

we know that

The <u>distance formula</u> is derived by creating a triangle and using the Pythagorean theorem to find the length of the hypotenuse. The hypotenuse of the triangle is the distance between the two points

The formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

A(1, 1) and B(7, −7)

Let

(x1,y1)=A(1, 1)

(x2,y2)=B(7, −7)

substitute the given values in the formula

dAB=\sqrt{(-7-1)^{2}+(7-1)^{2}}

dAB=\sqrt{(-8)^{2}+(6)^{2}}

dAB=\sqrt{64+36}

dAB=\sqrt{100}

dAB=10\ units

6 0
2 years ago
Read 2 more answers
Write and solve an inequality to find the values of x for which the perimeter of the rectangle is less than 120.
RSB [31]

Answer:

Inequality : 4x+8 < 120

x<28

Step-by-step explanation:

Hi, to answer this question we have to apply the next formula:

Perimeter of a rectangle (P)= 2 length +2 width

Where:

Width = x

Length = x+4

Replacing with the values given

P = 2 (x+4) + 2x

P = 2x+8+2x

P=4x+8

Since the perimeter of the rectangle must be less than 120:

4x+8 < 120

Solving for x

4x<120-8

4x<112

x<112/4

x<28

Feel free to ask for more if needed or if you did not understand something.  

4 0
2 years ago
The vertices of quadrilateral EFGH are listed below.
pav-90 [236]
It is going robe f help me ?
6 0
3 years ago
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