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2 years ago

L=U²A divided by (A+B)² make A the subject of formular

Mathematics

1 answer:

nikklg [1K]2 years ago

6 0

Answer:

A = [- 2Bl + U^2 +/- √((2BL - U^2)^2 - 4B^2L^2) ] / 2L

Step-by-step explanation:

L = U^2A / (A + B)^2

U^2 A = L(A^2 + 2AB + B^2)

U^2 A = LA^2 + 2ABL + B^2L

LA^2 + 2ABL - U^2A + B^2 L = 0

LA^2 + (2BL - U^2)A + B^2L = 0

Using the quadratic formula

A = [- (2BL - U^2) +/- √[(2BL - U^2)^2 - 4*L*B^2L] / 2L

A = [- 2BL + U^2 +/- √[(2BL - U^2)^2 - 4B^2L^2) ] / 2L

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PLSSSSSS HELP GIVING 10 POINTS

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Answer:

I'm pretty sure that it's C.

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3 years ago

Many people enjoy challenging themselves by running in marathons. A marathon is a 26-mile race. The runners wear numbers that id

Rudiy27

First we clear y from the given equation
x + 10y = 260
10y = 260-x
y = (260-x) / (10)
Then, we evaluate the function within the domain of it
x = 0
y = (260- (0)) / (10)
y = (260) / (10)
y = 26
x = 10
y = (260- (10)) / (10)
y = (250) / (10)
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That is, you travel 1 mile in 10 minutes.
Therefore, traveling 26 miles will take:
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6 0

3 years ago

Read 2 more answers

Which of the following ( 15, 20, 30, 57 ) is the product of exactly three different prime numbers?

Andrei [34K]

Answer:

30=2*3*5, so it's 30

Step-by-step explanation:

15=3*5, so it's not 15

20=2*2*5, so it's not 20

30=2*3*5, so it's 30

57=19*3, so it's not 57

3 0

2 years ago

Evaluate the integral ∫2−1|x−1|dx

defon

I think you might be referring to the definite integral,

$\displaystyle \int_{-1}^2|x-1|\,\mathrm dx$

Recall the definition of absolute value:

$|x| = \begin{cases}x&\text{if }x\ge0\\-x&\text{if }x$

Then $|x-1|=x-1$ if $x\ge1$ , and $|x-1|=1-x$ is $x$ . So spliting up the integral at x = 1, we have

$\displaystyle \int_{-1}^2|x-1|\,\mathrm dx = \int_{-1}^1(1-x)\,\mathrm dx + \int_1^2(x-1)\,\mathrm dx$

The rest is simple:

$\displaystyle \int_{-1}^2|x-1|\,\mathrm dx = \left(x-\dfrac{x^2}2\right)\bigg|_{-1}^1 + \left(\dfrac{x^2}2-x\right)\bigg|_1^2 \\\\ = \left(\left(1-\frac12\right)-\left(-1-\frac12\right)\right) + \left(\left(2-2\right)-\left(\frac12-1\right)\right) \\\\ = \boxed{\frac52}$