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3 years ago

L=U²A divided by (A+B)² make A the subject of formular

Mathematics

1 answer:

nikklg [1K]3 years ago

6 0

Answer:

A = [- 2Bl + U^2 +/- √((2BL - U^2)^2 - 4B^2L^2) ] / 2L

Step-by-step explanation:

L = U^2A / (A + B)^2

U^2 A = L(A^2 + 2AB + B^2)

U^2 A = LA^2 + 2ABL + B^2L

LA^2 + 2ABL - U^2A + B^2 L = 0

LA^2 + (2BL - U^2)A + B^2L = 0

Using the quadratic formula

A = [- (2BL - U^2) +/- √[(2BL - U^2)^2 - 4*L*B^2L] / 2L

A = [- 2BL + U^2 +/- √[(2BL - U^2)^2 - 4B^2L^2) ] / 2L

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A quality control engineer is interested in estimating the proportion of defective items coming off a production line. In a samp

fenix001 [56]

Answer:

The lower bound of a 99% C.I for the proportion of defectives = 0.422

Step-by-step explanation:

From the given information:

The point estimate = sample proportion $\hat p$

$\hat p = \dfrac{x}{n}$

$\hat p = \dfrac{55}{100}$

$\hat p$ = 0.55

At Confidence interval of 99%, the level of significance = 1 - 0.99

= 0.01

$Z_{\alpha/2} =Z_{0.01/2} \\ \\ = Z_{0.005} = 2.576$

Then the margin of error $E = Z_{\alpha/2} \times \sqrt{\dfrac{\hat p(1-\hat p)}{n}}$

$E = 2.576 \times \sqrt{\dfrac{0.55(1-0.55)}{100}}$

$E = 2.576 \times \sqrt{\dfrac{0.2475}{100}}$

$E = 2.576 \times0.04975$

E = 0.128156

E ≅ 0.128

At 99% C.I for the population proportion p is: $\hat p - E$

= 0.55 - 0.128

= 0.422

Thus, the lower bound of a 99% C.I for the proportion of defectives = 0.422

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3 years ago

What would the integer 500 equal using powers of 10? How did you come up with that answer?

strojnjashka [21]

Hello,

500=10^x
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3 years ago

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docker41 [41]

Answer: y=12.287

Step-by-step explanation:

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3 years ago

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the distance between california and mexico border is 100 miles less than thrice the distance between california and washington.

harina [27]

Answer: B. 3m-100

Step-by-step explanation:

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2 years ago

What is PA <br> Enter your answer in the box

SSSSS [86.1K]

Answer:

Step-by-step explanation:

P is the in-center

⇒PA=PE=PD because they are in-radius of the in-circle

We know that, tangent segments drawn from a point outside the circle are always equal in length

⇒DK=EK=7.2

In right triangle PKE,

using Pythagoras' Theorem : $PK^{2}=PE^{2}+KE^{2}$

⇒ $PE^{2}=PK^{2}-KE^{2}$

⇒ $PE=\sqrt{PK^{2}-KE^{2} }$

⇒ $PE^{2}=\sqrt{7.8^{2}-7.2^{2}} }$

⇒ $PE=3$

Therefore, $PA=3$

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3 years ago

L=U²A divided by (A+B)² make A the subject of formular​

L=U²A divided by (A+B)² make A the subject of formular