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2 years ago

L=U²A divided by (A+B)² make A the subject of formular

Mathematics

1 answer:

nikklg [1K]2 years ago

6 0

Answer:

A = [- 2Bl + U^2 +/- √((2BL - U^2)^2 - 4B^2L^2) ] / 2L

Step-by-step explanation:

L = U^2A / (A + B)^2

U^2 A = L(A^2 + 2AB + B^2)

U^2 A = LA^2 + 2ABL + B^2L

LA^2 + 2ABL - U^2A + B^2 L = 0

LA^2 + (2BL - U^2)A + B^2L = 0

Using the quadratic formula

A = [- (2BL - U^2) +/- √[(2BL - U^2)^2 - 4*L*B^2L] / 2L

A = [- 2BL + U^2 +/- √[(2BL - U^2)^2 - 4B^2L^2) ] / 2L

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we will proceed to resolve each case to determine the solution

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we know that

If an ordered pair is the solution of the inequality, then it must satisfy the inequality.

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Substitute the value of x and y in the inequality

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Substitute the value of x and y in the inequality

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Verify

using a graphing tool

see the attached figure

the solution is the shaded area below the line

The points A and D lies on the shaded area, therefore the ordered pairs A and D are solution of the inequality

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L=U²A divided by (A+B)² make A the subject of formular​

L=U²A divided by (A+B)² make A the subject of formular