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madreJ [45]
3 years ago
6

Bill has 5 times as many baseball cards as Fred. Tim has 3 fewer than 4 times as many baseball cards as Fred. In all they have 1

67 baseball cards. How many does each have
Mathematics
1 answer:
son4ous [18]3 years ago
6 0
67, 40 and 60 is how many each has
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X over 3 equals 1 over 4. how do i solve this in algebra? its solving one-step equations.
Snezhnost [94]

Cross multiply  X×4=3×1 4x=3 X= 3/4

6 0
3 years ago
Please help me it is due in 10 minutes
MAXImum [283]

Answer:

whooops no one had answered u from 50 min!

3 0
2 years ago
A local eat-in pizza restaurant wants to investigate the possibility of starting to deliver pizzas. The owner of the store has d
Alinara [238K]

Answer:

Read step by step explanation

Step-by-step explanation:

The owner already knows that the limit for the average time delivered pizzas is 38 minutes. So we conclude

1.-The resulting mean from sample data ( x ) ( 27 customers) need to be smaller than 38 minutes, any value of sample above 38 minutes means more time for the delivery action and will indicate a failure for the future project

2.-As sample size is smaller than 30 the test has to be  t-student one tail test to the left

Test hypothesis

Null hypothesis                       H₀                  x  = 38

Alternative hypothesis           Hₐ                  x  <  38

We should test at a significance level α  = 0,05       (α = 5%)

If the result of the test is to accept  H₀  delivery project won´t be implemented, if on the other hand, H₀ is rejected then in the condition of the alternative hypothesis we accept Hₐ the sample indicates that we have a smaller average time than 38 minutes.

4 0
3 years ago
PLEASE HELP ME FOR A TEST AND SELECT ALL THAT APPLY!!!!!!! 5 STARS!!!!!!!
MAVERICK [17]

Answer: 9-2 & -2-(-9)

Correct me if I'm wrong.

Step-by-step explanation:

5 0
2 years ago
How many sequences of 0s and 1s of length 19 are there that begin with a 0, end with a 0, contain no two consecutive 0s, and con
sladkih [1.3K]

65 sequences.

Lets solve the problem,

The last term is 0.

To form the first 18 terms, we must combine the following two sequences:

0-1 and 0-1-1

Any combination of these two sequences will yield a valid case in which no two 0's and no three 1's are adjacent

So we will combine identical 2-term sequences with identical 3-term sequences to yield a total of 18 terms, we get:

2x + 3y = 18

Case 1: x=9 and y=0

Number of ways to arrange 9 identical 2-term sequences = 1

Case 2: x=6 and y=2

Number of ways to arrange 6 identical 2-term sequences and 2 identical 3-term sequences =8!6!2!=28=8!6!2!=28

Case 3: x=3 and y=4

Number of ways to arrange 3 identical 2-term sequences and 4 identical 3-term sequences =7!3!4!=35=7!3!4!=35

Case 4: x=0 and y=6

Number of ways to arrange 6 identical 3-term sequences = 1

Total ways = Case 1 + Case 2 + Case 3 + Case 4 = 1 + 28 + 35 + 1 = 65

Hence the number of sequences are 65.

Learn more about Sequences on:

brainly.com/question/12246947

#SPJ4

8 0
2 years ago
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