(t^2+1)^100
USE CHAIN RULE
Outside first (using power rule)
100*(t^2+1)^99 * derivative of the inside
100(t^2+1)^99 * d(t^2+1)
100(t^2+1)^99 * 2t
200t(t^2+1)^99
Answer: $216
Step-by-step explanation:
Hope it helped
The answer is 4.9. 32/26=6/x, cross multiple to get 32x=156, divide by 32 to get x=4.875~4.9
Answer:
(4.1000)+ (2.100) + (7.10)
Your answer will be H 170
