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Phoenix [80]
2 years ago
12

When cream mixes with coffee, is this a chemical or physical change?

Chemistry
1 answer:
svlad2 [7]2 years ago
7 0

It is a physical change when cream mixes with coffee, it changes the color of the coffee. When you add more or less cream there is a color change depending on the consistency of cream. The properties are not changes and a no new compound is formed as in chemical change with a reaction of two compounds, a new compound is formed with different properties. So it is a physical change.

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You put two open cans of soda on the table. You took one can from the refrigerator and the other from your car. When you open th
sladkih [1.3K]
The correct answer from the choices given is the last option. The can from the <span> car will lose the carbon more quickly because there are fewer solute–solvent collisions. The can in the car has a lower temperature than the one in the refrigerator. At low temperature, the solubility of carbon dioxide in the liquid decrease therefore particles would tend to be in the vapor phase and escape from the liquid.</span>
6 0
3 years ago
A goldsmith melts 12.4 grams of gold to make a ring. The temperature of the gold rises from 26°C to 1064°C, and then the gold me
DiKsa [7]

Problem One

You will use both m * c * deltaT and H = m * heat of fusion.

Givens

m = 12.4 grams

c = 0.1291

t1 = 26oC

t2 = 1204

heat of fusion (H_f) = 63.5 J/grams.

Equation

H = m * c * deltaT + m * H_f

Solution

H = 12.4 * 0.1291 * (1063 - 26) + 12.4 * 63.5

H = 1660.1 + 787.4

H = 2447.5 or 2447.47 is the exact answer. I have to leave the rounding to you. I have no idea where to round it although I suspect 2450 would be right for 3 sig digs.

Problem Two

Formula and Givens

t1 = 14.5

t2 = 50.0

E = 5680

c = 4.186

m = ??

E = m c * deltaT

Solution

5680 = m * 4.186 * (50 - 14.5)

5680 = m * 4.186 * (35.5)

5680 = m * 148.603 * m

m = 5680 / 148.603

m = 38.22 grams That isn't very much. Be very sure you are working in joules. You'd leave that many grams in the kettle after drying it thoroughly.

m = 38.2 to 3 sig digs.

8 0
3 years ago
Read 2 more answers
The rate constant for the second-order reaction: 2NOBr(g) → 2NO(g) + Br2(g) is 0.80/(M · s) at 10°C. Starting with a concentrati
a_sh-v [17]

Answer : The concentration of NOBr after 95 s is, 0.013 M

Explanation :

The integrated rate law equation for second order reaction follows:

k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)

where,

k = rate constant = 0.80M^{-1}s^{-1}

t = time taken  = 95 s

[A] = concentration of substance after time 't' = ?

[A]_o = Initial concentration = 0.86 M

Now put all the given values in above equation, we get:

0.80=\frac{1}{95}\left (\frac{1}{[A]}-\frac{1}{(0.86)}\right)

[A] = 0.013 M

Hence, the concentration of NOBr after 95 s is, 0.013 M

4 0
2 years ago
Write a balanced equation for the following reaction:
tiny-mole [99]

Answer:

3AgCl + Na₃PO₄ —> 3NaCl + Ag₃PO₄

The coefficients are 3, 1, 3, 1

Explanation:

From the question given above, the following data were:

Silver chloride reacts with sodium phosphate to yield sodium chloride and silver phosphate. This can be written as follow:

AgCl + Na₃PO₄ —> NaCl + Ag₃PO₄

The above equation can be balanced as follow:

AgCl + Na₃PO₄ —> NaCl + Ag₃PO₄

There are 3 atoms of Na on the left side and 1 atom on the right side. It can be balance by putting 3 in front of NaCl as shown below:

AgCl + Na₃PO₄ —> 3NaCl + Ag₃PO₄

There are 3 atoms of Cl on the right side and 1 atom on the left. It can be balance by putting 3 in front of AgCl as shown below:

3AgCl + Na₃PO₄ —> 3NaCl + Ag₃PO₄

Thus, the equation is balanced.

The coefficients are 3, 1, 3, 1

6 0
3 years ago
What things typically are counted in multiples or fractions of moles
ololo11 [35]

Answer:

Individually well, defined identical chemically units such as molecules, ions, atoms, or electrons

Explanation:

The mole is used as the unit of measurement for substance such as molecules, ions, atoms, or electrons. One mole of a substance is equivalent to 6.02×10²³ particles of the substance. The number, 6.02 × 10²³ is known as Avogadro's number.

The particles quantified as moles are individually well, defined identical chemically units such that the mole can be used to describe a part of a substance or the whole substance consisting of several moles of the substance combined.

7 0
3 years ago
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