Answer:
pH = 8.34
Explanation:
The equilbriums of the amphoteric HCO₃⁻ (Ion of NaHCO₃) are:
H₂CO₃ ⇄ <em>HCO₃⁻</em> + H⁺ Ka1 <em>-Here, HCO₃⁻ is acting as a base-</em>
<em>HCO₃⁻</em>⇄ CO₃²⁻ + H⁺ Ka2 <em>-Here, is acting as an acid-</em>
Where Ka1 = 4.3x10⁻⁷ and Ka2 = 4.8x10⁻¹¹. As pKa = -log Ka:
pKa1 = 6.37; pKa2 = 10.32
As the pH of amphoteric salts is:
pH = (pKa1 + pKa2) / 2
<h2>pH = 8.34</h2>
The hydrogen and oxygen atoms that combine to form water molecules are bound together by covalent bonds. The electron from the hydrogen splits its time between the incomplete outer shell of the hydrogen atom and the incomplete outer shell of the oxygen atom.
<span>d. A catalyst will be used up in the reaction is wrong,
amount of catalyst should not change</span>
Answer:
The study is called ecology
Explanation:
Mark as brainliest if I'm correct
Answer:
Regarding Measures of center, the Mean will be smaller, and Median will not be affected. Thus, the median will not change, since the temperature was already low initially and only decreased. However, the median takes the average of all values into account, and if you substitute a value for a smaller value, the average decreases.
In relation to Measures of spread, the range and standard deviation will be larger, and the IQR will not change. Therefore, the range is the highest minus the lowest number; if the lowest number decreases sharply, the range increases. On the other hand, the IQR only counts the first and third quartile values. Therefore, since the value was already the lowest, if it is decreased, it will not change the IQR. However, the standard deviation will increase significantly, as the decreasing value of the lowest data point will increase the overall spread.
Explanation:
