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3 years ago

12-How many elements are in the mixture pictured below? A-7 O B-4 C-3 D-2

Chemistry

2 answers:

STALIN [3.7K]3 years ago

8 0

The answer is 3

The elements are red, black, and blue!

vovikov84 [41]3 years ago

4 0

Answer:

Explanation:

Because you don't count the dots. You count how many colors there are. Which are Blue, Red, and Black.

Hope this helped!

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Starting with 195 g Li2O and 106 g H2O, decide which reactant is present in limiting quantities. Given: Li2O+H2O→2LiOH

kkurt [141]

Taking into account the stoicionetry reaction and the definition of limiting reagent, Li₂O is present in limiting quantities.

The balanced reaction is:

Li₂O + H₂O → 2 LiOH

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Li₂O: 1 mole
H₂O: 1 mole
LiOH: 2 moles

The molar mass of each compound is:

Li₂O: 29.88 g/mole
H₂O: 18 g/mole
LiOH: 23.95 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

Li₂O: 1 mole× 29.88 g/mole= 29.88 g
H₂O: 1 mole× 18 g/mole= 18 g
LiOH: 2 moles× 23.95 g/mole= 47.9 g

On the other side, the limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 18 grams of H₂O reacts with 29.88 grams of Li₂O, 106 grams of H₂O react with how much mass of Li₂O?

$mass of Li_{2} O=\frac{29.88 grams of Li_{2} Ox106 grams of H_{2} O}{18 grams of H_{2} O}$

mass of Li₂O= 175.96 grams

But 175.96 grams of Li₂O are not available, 195 grams are available. Since you have less moles than you need to react with 106 grams of H₂O, Li₂O will be the limiting reagent.

Finally, Li₂O is present in limiting quantities.

Learn more:

4 0

3 years ago

A buffered solution containing dissolved aniline, C6H5NH2, and aniline hydrochloride, C6H5NH3Cl, has a pH of 5.57 . A. Determine

vlada-n [284]

Answer:

[C₆H₅NH₃⁺] = 0.0399 M

Explanation:

This excersise can be easily solved by the Henderson Hasselbach equation

C₆H₅NH₃Cl → C₆H₅NH₃⁺ + Cl⁻

pOH = pKb + log (salt/base)

As we have value of pH, we need to determine the pOH

14 - pH = pOH

pOH = 8.43 (14 - 5.57)

Now we replace data:

pOH = pKb + log ( C₆H₅NH₃⁺/ C₆H₅NH₂ )

8.43 = 9.13 + log ( C₆H₅NH₃⁺ / 0.2 )

-0.7 = log ( C₆H₅NH₃⁺ / 0.2 )

10⁻⁰'⁷ = C₆H₅NH₃⁺ / 0.2

0.19952 = C₆H₅NH₃⁺ / 0.2

C₆H₅NH₃⁺ = 0.19952 . 0.2 = 0.0399 M

5 0

3 years ago

Prove that PV = nRT.

qaws [65]

Find your answer in the explanation below.

Explanation:

PV = nRT is called the ideal gas equation and its a combination of 3 laws; Charles' law, Boyle's law and Avogadro's law.

According to Boyle's law, at constant temperature, the volume of a gas is inversely proportional to the pressure. i.e V = 1/P

From, Charles' law, we have that volume is directly proportional to the absolute temperature of the gas at constant pressure. i.e V = T

Avogadro's law finally states that equal volume of all gases at the same temperature and pressure contain the same number of molecules. i.e V = n

Combining the 3 Laws together i.e equating volume in all 3 laws, we have

V = nT/P,

V = constant nT/P

(constant = general gas constant = R)

V = RnT/P

by bringing P to the LHS, we have,

PV = nRT.

Q.E.D

6 0

3 years ago

Which of the following elements is in the same group as Sulfur (S)?

ikadub [295]

Answer:

<u><em>PLEASE SHOW ME THE ELEMENTS OR I WOULD ENLIST ALL THE ELEMENTS.</em></u>

Explanation:

Group 6A (or VIA) of the periodic table are the chalcogens: the nonmetals oxygen (O), sulfur (S), and selenium (Se), the metalloid tellurium (Te), and the metal polonium (Po)

4 0

3 years ago

Identify the atom that is oxidized, reducing agent, in the following equation: Zn(s) + H2SO4(aq) --> ZnSO4(aq) + H2(g)

Sav [38]

Answer:

The atom that is oxidized is Zn.

Explanation:

Reducing agents reduce other atoms or species by being oxidized themselves. Oxidation is a loss of electrons. In the equation, the Zn atom originally has an oxidation state of zero (neutral). On the right side of the equation, Zn is part of the ionic compound zinc sulfate, which is composed of the Zn(2+) cation and the SO4(2-) anion. The Zn(2+) ion is positive, which means it must have lost electrons (which have a negative charge), and was therefore oxidized from the neutral atom Zn(s).

5 0

3 years ago