1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anni [7]
3 years ago
13

Consider hydrogen atom in an excited state of 3s1. What is the energy of its electron

Chemistry
1 answer:
SVEN [57.7K]3 years ago
8 0

<u>Given:</u>

Excited state electron configuration of H atom = 3s¹

<u>To determine:</u>

Energy of the electron in this state

<u>Explanation:</u>

The energy 'E' of an electron in a hydrogen atom occupying a level, 'n' is given by the formula:

En = -E₀/n²

where, E₀ is the ground state energy = 13.6 eV

n = principle quantum number i.e. n = 1,2,3...

Therefore,

En = -13.6/n² eV

In this case for a 3s¹ configuration, n = 3

E = -13.6/(3)² = -1.51 eV

Ans: Energy of the electron in a 3s1 state is -1.51 eV

You might be interested in
A gas occupies a volume of 85.0 liters at a pressure of 2.24 atm and a temperature of 22.5 degrees celsius. How many moles of ga
White raven [17]

Answer:

n = 7.86 mol

Explanation:

This question can be solved using the ideal gas law of PV = nRT.

Temperature must be in K, so we will convert 22.5C to 295 K ( Kelvin = C + 273).

R is the ideal gas constant of 0.0821.

(2.24atm)(85.0L) = n(0.0821)(295K)

Isolate n to get:

n = (2.24atm)(85.0L)/(0.0821)(295K)

n = 7.86 mol

8 0
2 years ago
If 100 mL of a 12 M solution of HCl is diluted to a final volume of 500 mL, what would be the final concentration of the diluted
AURORKA [14]
Dilution formula:
mv = MV

where one side is concentration × volume BEFORE dilution and the other side is concentration × volume AFTER dilution. 

(100mL) × (12 M) = (500mL) × (X)
(1200 M·mL) = (500mL) × (X)
(1200 M·mL) / (500mL) = X
2.4 M = X

3 0
2 years ago
A sample of gas has a pressure of 742 torr. What is the pressure in atmospheres?
ycow [4]

Answer:742 torr= approximately 0.976 atm

Explanation:

Since we know that one atm= 760 torr, we can compute the following calculation:

(742 torr/1)*(1atm/760torr)=0.976316 atm

Remember sig figs (3) to round it to 0.976 atm

\frac{742 torr}{1}*\frac{1 atm}{760 torr}=0.976316=0.976 atm

(torr cancels out and we're left with atm)

Hope this helps :)

8 0
3 years ago
a gas has a volume of 750ml at pressure of 2.15atm what will the pressure be if the volume is 1.25ml​
Dmitry [639]

Answer:

1290 atm

Explanation:

P1V1=P2V2

P2= (P1V1)/V2

P2=(2.15 atm * 750 mL)/(1.25 mL)

P2=1290 atm

6 0
3 years ago
Which element has the electron configuration [Xe] 6s2 4f14 5d10 6p2?
andreev551 [17]
To determine the element that has an electron configuration of <span>[Xe] 6s2 4f14 5d10 6p2, we must know the atomic number of Xe. From the periodic table, Xe has an atomic number of 54. We add the proceeding electrons, which is now a total of 82. The element with this atomic number is lead, Pb.</span>
4 0
3 years ago
Other questions:
  • What is the reaction in which two or more reactants combine to give single product?​
    6·1 answer
  • why do chemist use relative masses of atoms compared to a refference isotope rather than the actual of the atoms
    9·1 answer
  • For which of the following equilibria does `"K"_("eq") = ["O"_2]`? A. O2(l) O2(g) B. 2O3(g) 3O2(g) C. 2H2O(l) 2H2(g) + O2(g) D.
    15·2 answers
  • I don’t understand it plz help
    11·1 answer
  • Print
    14·1 answer
  • If the temperature of a gas doubles and the volume stays the same, what will happen to the pressure?
    6·1 answer
  • Iodine 131, cesium 137, and strontium 90 are all considered isotopes. What are isotopes?
    15·2 answers
  • Rubidium has an atomic number of 37 and a mass number of 85. How many protons, neutrons, and electrons does an ion of rubidium w
    7·1 answer
  • Help with atoms WILL MARK BRAINLIEST
    14·1 answer
  • Why does the moon and the earth have the same mass
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!