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3 years ago

Consider hydrogen atom in an excited state of 3s1. What is the energy of its electron

Chemistry

1 answer:

SVEN [57.7K]3 years ago

8 0

<u>Given:</u>

Excited state electron configuration of H atom = 3s¹

<u>To determine:</u>

Energy of the electron in this state

<u>Explanation:</u>

The energy 'E' of an electron in a hydrogen atom occupying a level, 'n' is given by the formula:

En = -E₀/n²

where, E₀ is the ground state energy = 13.6 eV

n = principle quantum number i.e. n = 1,2,3...

Therefore,

En = -13.6/n² eV

In this case for a 3s¹ configuration, n = 3

E = -13.6/(3)² = -1.51 eV

Ans: Energy of the electron in a 3s1 state is -1.51 eV

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