The engineer would C. research new scientific findings about ocean cleanup.
A competent engineer would already know what has been done in the past to clean up oceanic oil residue.
Identifying needs and evaluating benefits and challenges are <em>value judgements</em> that are more appropriate for other decision-makers such as politicians.
Answer:
Explanation:
Use Dalton's law and the vapor pressure of water at 23.0 o C to correct the pressure to units of atmoshperes.
PT = Poxygen +Pwater
At 23.0 o C the vapor pressure of water is 21.1 mmHg. (This can be found on a vapor pressure table.)
762 mmHg = Poxygen + 21.1 mmHg
Poxygen = 762 mmHg - 21.1 mmHg
Poxygen =741 mmHg
Convert the corrected pressure to atmospheres.
(741 mmHg) (1 atm / 760 mmHg) = 0.975 atm
Use the ideal gas law to find out how many moles of gas were produced:
PV = nRT (remember to put volume in liters and temperature in Kelvin)
(0.975 atm) (.193 L) = n (.0821 L atm / mol K) (298 K)
n = (0.975 atm) (.193 L) / (.0821 L atm / mol K) (298 K)
n = 7.69 X 10-4 mol
Use the number of moles and the molecular weight of oxygen to find out how many grams of oxygen were collected.
(7.69 X 10-4 mol) (32.0 g / 1 mol) = 2.46 X 10-2 g
Answer:
C6 H10 O5+ 6O2-----> 6CO2+5H2O+heat
Explanation:
There are 6 carbon atoms in reactants to balance you put coefficient 6.
This makes the oxygen in CO2 12 so to balance put 6 in oxygen in reactants.
There are 10 hydrogen atoms in reactants to balance you put 5 in front of H2O in products.
If u recheck: 6 C atoms in reactants, 6 C atoms in products.
10 H atoms in reactants, 10 H atoms in products.
17 O atoms in reactants, 17 O atoms in products.
They do form directly on the equators
Moles of Carbon dioxide : 13.5
<h3>Further explanation</h3>
Given
4.5 moles propane
Required
moles of Carbon dioxide
Solution
Reaction(Combustion of Propane) :
<em>C₃H₈(g)+5O₂(g)→3CO₂(g)+4H₂O(g)</em>
In a chemical equation, the reaction coefficient shows the mole ratio of the reacting compounds (either in reactants or products)
From the equation, mol ratio of Propane(C₃H₈) : Carbon dioxide(CO₂) : 1 : 3, so mol CO₂ :
= 3/1 x mol Propane
= 3 x 4.5 moles
= 13.5 moles
