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lesya692 [45]
3 years ago
6

How do the number of electrons in the second energy shell of an atom change going across period 2 in the periodic table?

Chemistry
1 answer:
weqwewe [10]3 years ago
8 0
The answer should be A, the number of electrons increases by 1, from left to right.

Across the periods (horizontal direction) in periodic table, each element has one more electron then the one before it. The number of period determines the number of occupied electron shells of the elements in that period. Which means, period 1 elements have 1 occupied electron shell, period 2 has 2, period 3 has 3 etc.

Therefore, the answer is A, we always go from left to right, and plus since period 2 elements only have 2 occupied electrons so their 2nd electron shell electrons must increase throughout the period.
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The density of water is 1.00g/cm3. Express this density in lb/m3​
Ira Lisetskai [31]

Answer:  2205 lb/m^3

Explanation:  

  • 1g = 0.002205lb
  • 1cm^3 = 1x10^-6m^3

Convert:  (1g/cm^3)*(0.002205lb/g)*(1cm^3/1x10^-6m^3) = 2205 lb/m^3

           

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3 years ago
Which statement about astrology is not true? the positions of the planets at the time of birth have influence on a persons life
Anna71 [15]

Answer:

The positions of the planets at the time of birth have influence on a person's life

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The means of X ? ⊙_⊙⊙_⊙⊙_⊙​
julsineya [31]

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x means unknown it is an unknown value.

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5 0
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5.080 x 1016 molecules of hydrogen to moles
lawyer [7]
For this problem, to determine the number of moles given the number of molecules, we use the Avogadro's number. This is an empirical value that relates the number of particles (e.g. atoms, molecules, sub-particles) in one mole of any substance. The value is 6.022×10²³ molecules/mol.

5.080×10¹⁶ molecules * 1 mol/6.022×10²³ molecules = <em>8.436×10⁻⁸ moles of hydrogen</em>
3 0
3 years ago
At 20 ∘C the vapor pressure of benzene C6H6 is 75 torr and that of toluene C7H8 is 22 torr. Assume that benzene and toluene fo
Olegator [25]

Answer:

a) Xbenzene = 0.283

b) Xtoluene = 0.717

Explanation:

At T = 20°C:

⇒ vapor pressure of benzene (P*b) = 75 torr

⇒ vapor pressure toluene (P*t) = 22 torr

Raoult's law:

  • Pi = Xi.P*i

∴ Pi: partial pressure of i

∴ Xi: mole fraction

∴ P*i: vapor pressure at T

a) solution: benzene (b) + toluene (t)

∴ Psln = 37 torr;   at T=20°C

⇒ Psln = Pb + Pt

∴ Pb = (Xb)*(P*b)

∴ Pt = (Xt)*(P*t)

∴ Xb + Xt = 1

⇒ Psln = 37 torr = (Xb)(75 torr) + (1 - Xb)(22 torr)

⇒ 37 torr - 22 torr = (75 torr)Xb - (22 torr)Xb

⇒ 15 torr = 53 torrXb

⇒ Xb = 15 torr / 53 torr

⇒ Xb = 0.283

b) Xb + Xt = 1

⇒ Xt = 1 - Xb

⇒ Xt = 1 - 0.283

⇒ Xt = 0.717

6 0
4 years ago
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