Answer:
The mass of gold is found to be 310.34 g.
Explanation:
We have:
Specific heat of gold = C = 0.130 J/g.°C
Heat = H = 468 J
Change in Temperature = ΔT = 33.2 °C - 21.6 °C = 11.6 °C
Now, to find mass of gold we first calculate the amount of heat required to heat the unit mass of gold to specified temperature:
Mass Specific Heat = C * ΔT
Mass Specific Heat = (0.130 J/g.°C)(11.6 °C)
Mass Specific Heat = 1.508 J/g
Now, for the mass of gold (m):
mass of gold = Heat/Mass Specific Heat
mass of gold = 468 J/1.508 J/g
<u>mass of gold = 310.34 g</u>
Answer: 44.8 L
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number of particles.
Standard condition of temperature (STP) is 273 K and atmospheric pressure is 1 atm respectively.
To calculate the moles, we use the equation:
1 mole of occupies volume = 22.4L at STP
Thus 2 moles of magnesium react with=
Thus the volume of molecules of nitric oxide gas is 44.8 L.
Answer:
Explanation:
1. Convert millilitres to litres
2. Calculate the concentration
Answer:
f = V / λ
Explanation:
In this formula, f represents frequency, V represents the velocity of the wave, and λ represents the wavelength of the wave