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Alecsey [184]
3 years ago
8

draw a representation that shows the interactions between the solute and solvent in an aqueous solution of potassium bromide

Chemistry
1 answer:
Svetllana [295]3 years ago
3 0
The visualization of the solute and solvent in an aqueous solution is such that the solute molecules are surrounded by solvent molecules, which in this case is water.

The potassium bromide will be found in the form of potassium and bromide ions. Both of these ions will be surrounded by water molecules. In the case of potassium, because it is a positively charged ion, the oxygen atoms of the water molecules will be close to the ion and the hydrogen atoms will be on the other side. The opposite will occur with the bromide ions due to their negative charge.
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Which combination of elements are most likely to react to form ionic compounds
Nat2105 [25]
Ionic compounds form between metals and non metals.
7 0
3 years ago
In the phase diagram below, point B describes the critical point.<br><br><br><br> TRUE<br><br> FALSE
White raven [17]
The critical point is said to be the end point of a phase diagram. The most known example is the liquid-vapor critical point, the point in a PT curve that signifies that at this point both vapor and liquid coexist. The critical point is characterized by a critical pressure and a critical temperature.
4 0
3 years ago
Balance the following chemical equations.
solong [7]

Answer:

1) 2,1,2

2) 2,2,1,1

3)2,1,2

4)2,2,3

5)2,3,1,3

6 [ I cannot answer that]

7)6,1,2

3 0
4 years ago
14.
Vesnalui [34]

Answer:

Mass = 72.52 g

Explanation:

Given data:

Mass of hydrogen phosphate produced = ?

Mass of P₂O₅ react = 105.9 g

Solution:

Chemical equation:

P₂O₅ + 3H₂O     →     2H₃PO₄

Number of moles of P₂O₅:

Number of moles = mass/molar mass

Molar mass of P₂O₅ 283.9 g/mol

Number of moles = 105.9 g/ 283.9 g/mol

Number of moles = 0.37 mol

Now we will compare the moles of P₂O₅ with H₃PO₄ from balance chemical equation.

                     P₂O₅        :         H₃PO₄

                         1           :           2

                      0.37        :        2/1×0.37= 0.74 mol

Mass of H₃PO₄ :

Mass = number of moles × molar mass

Mass = 0.74 mol ×  98 g/mol

Mass = 72.52 g

7 0
3 years ago
According to Archimedes' principle, the mass of a floating object equals the mass of the fluid displaced by the object. A 150-lb
julsineya [31]

Answer:

The density of the swimmer is 0.0342 lbm/in3.

This value makes sense as the density of the body is very similar to the water.

Explanation:

If the swimmers is floating, the weight of the swimmer must be equal to the upward buoyant force.

We can express the weight force as the product of density and volume of the swimmer.

Then

\rho_{swimmer}*V_{swimmer}=\rho_{water}*V_{water_displaced}\\\\\rho_{swimmer}*V_{swimmer}=\rho_{water}*0.95**V_{swimmer}\\\\\rho_{swimmer}=0.95*\rho_{water}\\\\\rho_{swimmer}=0.95*0.036 lbm/in3\\\\\rho_{swimmer}=0.0342lbm/in3

It makes sense as the density of the body is very similar to the water.

5 0
3 years ago
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