The amount, in grams, of N that the sample will contain will be 2.1 grams.
<h3>Stoichiometric mass ratio</h3>
According to the problem. the mass ratio of H and N in ammonia is 4.7:1.
In other words, every 4.7 grams of H in ammonia must have 1 gram of N.
Now, in a particular ammonia sample, 10 grams of H is present.
The amount of N present can be calculated from the standard mass ratio.
4.1 grams H = 1 gram N
10 grams H = x
4.1x = 1 x 10
x = 10/4.1
x = 2.1 grams
Thus, the mass of nitrogen in the ammonia sample will be 2.1 grams.
More on mass ratios can be found here: brainly.com/question/14577772
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Answer : The enthalpy change for the reaction is 1043 kJ/mol.
Explanation :
The given chemical reaction is:
As we know that:
The enthalpy change of reaction = E(bonds broken) - E(bonds formed)
![\Delta H=[(2\times B.E_{C\equiv O})+(1\times B.E_{O\equiv O})]-[2\times B.E_{C=O}]](https://tex.z-dn.net/?f=%5CDelta%20H%3D%5B%282%5Ctimes%20B.E_%7BC%5Cequiv%20O%7D%29%2B%281%5Ctimes%20B.E_%7BO%5Cequiv%20O%7D%29%5D-%5B2%5Ctimes%20B.E_%7BC%3DO%7D%5D)
Given:
= 1074 kJ/mol
= 499 kJ/mol
= 802 kJ/mol
Now put all the given values in the above expression, we get:
![\Delta H=[(2\times 1074kJ/mol)+(1\times 499kJ/mol)]-[2\times 802kJ/mol]](https://tex.z-dn.net/?f=%5CDelta%20H%3D%5B%282%5Ctimes%201074kJ%2Fmol%29%2B%281%5Ctimes%20499kJ%2Fmol%29%5D-%5B2%5Ctimes%20802kJ%2Fmol%5D)
Therefore, the enthalpy change for the reaction is 1043 kJ/mol.
<u>Answer:</u> The partial pressure of oxygen is 160 mmHg
<u>Explanation:</u>
We are given:
Percent of oxygen in air = 21 %
Mole fraction of oxygen in air = 
To calculate the partial pressure of oxygen, we use the equation given by Raoult's law, which is:
where,
= partial pressure of oxygen = ?
= total pressure of air = 760 mmHg
= mole fraction of oxygen = 0.21
Putting values in above equation, we get:
Hence, the partial pressure of oxygen is 160 mmHg
Taking into account the scientific notation, the result of the subtraction is -4.20689×10⁻².
<h3>Scientific notation</h3>
Scientific notation is a quick way to represent a number using powers of base ten, where the numbers are written as a product:
a×10ⁿ
where:
- a is a real number greater than or equal to 1 and less than 10, to which a decimal point is added after the first digit if it is a non-integer number.
- n is an integer, which is called an exponent or an order of magnitude. Represents the number of times the comma is shifted. It is always an integer, positive if it is shifted to the left, negative if it is shifted to the right.
<h3>Subtraction in scientific notation</h3>
When the numbers to be added do not have the same base 10 exponent, the base 10 power with the highest exponent must be found. In this case, the highest exponent is -2.
Then all the values are expressed as a function of the base 10 exponent with the highest exponent. In this case: 3.11×10⁻⁵= 0.00311×10⁻²
Taking the quantities to the same exponent, all you have to do is subtract what was previously called the number "a". In this case:
0.00311×10⁻² - 4.21×10⁻²= (0.00311 - 4.21)×10⁻²= -4.20689×10⁻²
Finally, the result of the subtraction is -4.20689×10⁻².
Learn more about operations in scientific notation:
brainly.com/question/1894247
brainly.com/question/11403716
brainly.com/question/853571
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