All categories

3 years ago

Como se hace -8n+7=31

Mathematics

1 answer:

velikii [3]3 years ago

8 0

-8n+7=31
-8n+7-7=31-7
-8n=31-7
-8n=24
-8n÷(-8)=24÷(-8)
n=24÷(-8)
n=-24÷8
n=-3

You might be interested in

The graph of g(x), shown below, is a vertical shift of the graph of f(x) = 2x.

4vir4ik [10]

The equation which represents the given graph g(x) is 2ˣ-1.

<h3>What is Equation?</h3>

Equations are mathematical statements containing two algebraic expressions on both sides of an 'equal to (=)' sign.

Here, given graph passes through origin.

Put x = 0 in all the given equation and verify which equations gives result as zero.

Put x = 0 in option A

g(0) = 2⁰⁺¹ = 2 ≠ 0

in option B

g(0) = 2⁰-1 = 1 - 1 = 0

Thus, option B g(x) = 2ˣ-1 is the correct expression for the given graph.

Learn more about Equations from:

brainly.com/question/10413253

#SPJ1

3 0

2 years ago

Thank you all for helping me with every thing! I also need help with this one :)

Flauer [41]

Answer:

1.5/6

2.1/6

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

I need help with a math problem

soldi70 [24.7K]

Answer:

19,680

Step-by-step explanation:

1 lb = 16 ounces

1230 lb = 1230 * 16 ounces = 19,680 ounces

5 0

3 years ago

The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The d

kozerog [31]

Answer: 49.85%

Step-by-step explanation:

Given : The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The distribution of the number of daily requests is bell-shaped ( normal distribution ) and has a mean of 61 and a standard deviation of 9.

i.e. $\mu=61$ and $\sigma=9$

To find : The approximate percentage of lightbulb replacement requests numbering between 34 and 61.

i.e. The approximate percentage of lightbulb replacement requests numbering between 34 and $34+3(9)$ .

i.e. i.e. The approximate percentage of lightbulb replacement requests numbering between $\mu$ and $\mu+3(\sigma)$ . (1)

According to the 68-95-99.7 rule, about 99.7% of the population lies within 3 standard deviations from the mean.

i.e. about 49.85% of the population lies below 3 standard deviations from mean and 49.85% of the population lies above 3 standard deviations from mean.

i.e.,The approximate percentage of lightbulb replacement requests numbering between $\mu$ and $\mu+3(\sigma)$ = 49.85%

⇒ The approximate percentage of lightbulb replacement requests numbering between 34 and 61.= 49.85%

4 0

3 years ago

Evaluate. 75-2(9-5)²+2³

Andreyy89