The answer would be:
A. Cancel out CO because it appears as a reactant in one intermediate reaction and a product in the other intermediate reaction.
In this question, there are two half-reaction equations. To merge them up, you need to add the reactant with the reactant, then the product with the product. If there is a molecule on both side, you can cancel them. The full reaction would be:
C+ 1/2 O2 + CO + 1/2O2 ==>CO+ CO2 -----> remove CO from both side
C+ O2 ==>CO2
Answer:- Specific gravity of glucose solution is 1.02.
Solution:- Specific gravity is the ratio of the compound density with water density, means how denser the compound solution is as compared to water.
specific gravity = 
density of glucose is given as 1.02 g per mL and water density is 1.00 g per mL.
Let's plug in the values in the formula:
specific gravity = 
= 1.02
So, the specific gravity of glucose is 1.02. It indicates that glucose is 1.02 times more denser than water.
Chaetoceros is planktonic diatoms and known to be the largest genus with 400 described species. It has a cell wall made up of silica containing long thin spins. These spines connect the cell walls together to form a colony of cells.
Due to its high rate of growth and high lipid concentration, they can be used as bio fuel. Colonies of chaetoceros act as an important food source inside the water and they are major contributor of carbon.
In north water, they contribute 91% of the total phytoplankton cells thus acting as an important producer in the area. This contributes to the production of oxygen in north water. Total phytoplankton contributes to half of the oxygen production of Earth.
In this way, chaetoceros contribute to global atmospheric oxygen and carbon dioxide levels.
Answer:
Explanation:
Phosphoric acid H₃PO₄ is produced from reaction of water and tetraphosphorus decoxide P₄O₁₀ as follows
P₄O₁₀ + 6 H₂O = 4 H₃PO₄
In this reaction 6 molecules of H₂O and one molecule of phosphorus compound P₄O₁₀ is needed to produce phosphoric acid , ie the conversion factor of water to acid is 6 / 1
This ratio is called mole ratio of water to H₃PO₄.
So the required ratio is 6 : 1 .
Answer:
2.15 mg of uranium-238 decays
Explanation:
For decay of radioactive nuclide-
where N is amount of radioactive nuclide after t time, 
is initial amount of radioactive nuclide and 
is half life of radioactive nuclide
Here 
, 
and 
So,
so, N = 2.446 mg
mass of uranium-238 decays = (4.60-2.446) mg = 2.15 mg
