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devlian [24]
3 years ago
9

What is the mole ratio of water to H3PO4?

Chemistry
1 answer:
Artyom0805 [142]3 years ago
3 0

Answer:

Explanation:

Phosphoric acid H₃PO₄ is produced from reaction of water and tetraphosphorus decoxide  P₄O₁₀ as follows

P₄O₁₀ + 6 H₂O = 4 H₃PO₄

In this reaction 6 molecules of H₂O and one molecule of  phosphorus compound P₄O₁₀ is needed to produce phosphoric acid , ie the conversion factor of water to acid is 6 / 1

This ratio is called mole ratio of water to H₃PO₄.

So the required ratio is 6 : 1 .

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An open system is one where mass is able to flow in and out of the system. The mass entering this system is the water that is added to the fish tank, and the leaving mass is the waste that is generated.


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A baby weighs 7 pounds, 4 ounces at birth and 7 pounds, I ounce at discharge. What percent of weight did the baby lose
Aloiza [94]

Answer:

2.6%

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As, 1 ounce (oz) =  0.0625 pounds (lb)

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6 0
4 years ago
PLEASE HELP WILL GIVE BRAINLIEST
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Answer:

16. Option c.

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The reaction is:

C₈H₁₈ + O₂  →  CO₂ + H₂O

Let's count, we have 8 C, 18 H and 2 O in reactant side

We have 1 C, 2 H and 3 O  in product side

In order to balance the C, we add 8 to CO₂ and to balance the H, we add a 9 to H₂O

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2C₈H₁₈ + 25O₂  →  16CO₂ + 18H₂O

with 16 C, 36 H and 50 O, on both sides

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