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2 years ago

What is the mole ratio of water to H3PO4?

Chemistry

1 answer:

Artyom0805 [142]2 years ago

3 0

Answer:

Explanation:

Phosphoric acid H₃PO₄ is produced from reaction of water and tetraphosphorus decoxide P₄O₁₀ as follows

P₄O₁₀ + 6 H₂O = 4 H₃PO₄

In this reaction 6 molecules of H₂O and one molecule of phosphorus compound P₄O₁₀ is needed to produce phosphoric acid , ie the conversion factor of water to acid is 6 / 1

This ratio is called mole ratio of water to H₃PO₄.

So the required ratio is 6 : 1 .

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If the concentrated form of blood expander is 9.0 mol/L and one of your companions, a nurse, tells you that you need to have a f

I am Lyosha [343]

Answer:

0.032 L or 32 mL

Explanation:

Use the dilution equation M1V1 = M2V2

M1 = 9.0 M

V1 = This is what we're looking for.

M2 = 0.145 M

V2 = 2 L

Solve for V1 --> V1 = M2V2/M1

V1 = (0.145 M)(2 L) / (9.0 M) = 0.032 L

3 0

3 years ago

A student was comparing two samples with an equal number of carbon atoms. One sample contained only Carbon-12 atoms. One sample

Diano4ka-milaya [45]

Answer:

3.14

Explanation:

A student was comparing two samples with an equal number of carbon atoms. One sample contained only Carbon-12 atoms. One sample contained only Carbon-14 atoms, which contain two more neutrons than Carbon-12 atoms. The student measured the mass of each sample and testing the reactivity of each sample.

Required:

What would best describe the results of the investigation?

3 0

1 year ago

1. Which variable is the independent variable and which is the dependent variable? Density vs. ethylene glycol

AnnyKZ [126]

<span>1. Which variable is the independent variable and which is the dependent variable? Density vs. ethylene glycol
The independent variable would be ethylene glycol and dependent variable would be density.

A. A 25-mL volumetric flask with its stopper has a mass of 32.6341 g. The same flask filled to the line with ethylene glycol (C2H6O2, automotive antifreeze) solution has a mass of 58.0091 g. What is the density of the ethylene glycol solution?

Density = 58.0091 - 32.6341 / .025 = 1015 g/L

B. What is the molarity of the ethylene glycol solution, if the mass of ethylene glycol in the solution is 12.0439 g?

Molarity = 12.0439 ( 1 mol / 62.07 g) / 0.025 = 7.8 M</span>

5 0

2 years ago

Read 2 more answers

A sample 0.100 moles of a gas is collected at at stp. what is the volume of the gas in liters? group of answer choices 2.44 l

bearhunter [10]

n = 0.100 moles

At STP (standard temperature pressure), where gas is collected, the temperature is 0°C and the pressure is 1 atm.

$\\$\therefore$ Temperature $(T)=0^{\circ} \mathrm{C}=0^{\circ}+273$

$=273K$

$Pressure $(P)=1$ atm.$

The ideal gas equation indicates that

$\begin{aligned}& P V=n R T \Rightarrow V=\frac{n R T}{P} \\\therefore & R=\text { gas constant }=0.0821 \mathrm{~L} \cdot \mathrm{cetm} / \mathrm{mo} / \cdot K\end{aligned}$

$\begin{aligned}&V=\frac{0.100 \mathrm{~mol} \cdot \times 0.0821 \mathrm{~L} \cdot \mathrm{atm} / \mathrm{mol} . \mathrm{K} \times 273 \mathrm{~K}}{1 \mathrm{~atm}} \\&V=\frac{2.24 L}{1}\end{aligned}\\$

$V=2.24L$

Group of answer choices $2.44L$ .The volume occupied by mole of a given gas at a given temperature and pressure is expressed as the gas's molar volume.

The most typical illustration is the molar volume of a gas at STP, which is equal to $2.44L$ for $1$ mole of any ideal gas at a temperature of $273.15$ Kand a pressure of $1$ atm.

Hence, the volume of the gas is $2.24L$ .

A unit is stated to have a temperature of absolute zero $(273 Kelvins)$ and an atmospheric pressure of one atmosphere, or $1$ atm, at standard temperature and pressure. Additionally, at STP, a mole of any gas takes up $22.414 L$ of space. Keep in mind that this idea only applies to gases.

For experimental measurements to be established under standard conditions that allow for comparisons between various sets of data, standard temperature and pressure must be met.

To learn more about STP, Visit:

brainly.com/question/1626157

#SPJ4

8 0

1 year ago

In the reaction _Al 3O2→2Al2O3, what coefficient should be placed in front of the Al to balance the reaction? 1 2 3 4.

luda_lava [24]

Answer:

D.) 4

Explanation:

Al + 3 O₂ --> 2 Al₂O₃

In the equation, there are:

<em>Reactants:</em> 1 Al and 6 O

<em>Products:</em> 4 Al and 6 O

To determine how many atoms there are of each, you multiply the coefficients by the subscripts attached to the atoms. While the question doesn't ask, as you can see, the oxygen atoms are balanced because there is an equal amount on both sides. To balance the aluminum atoms, you can get 4 aluminum atoms on the reactants side by using a coefficient of 4.

The new equation would look this this:

4 Al + 3 O₂ --> 2 Al₂O₃

There are now:

<em>Reactants:</em> 4 Al and 6 O

<em>Products:</em> 4 Al and 6 O

4 0

1 year ago