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Serjik [45]
3 years ago
6

The proton number of barium (Ba) is 56. It is in Group II of the periidic table how many electrons would you expect a barium ato

m to contain in its outer energy level?
Chemistry
1 answer:
ella [17]3 years ago
7 0

Answer:

A barium atom would be expected to contain 2 electrons in its outer energy level.

Explanation:

The columns of the periodic table are called groups. There are eighteen groups, numbered from 1 to 18.

The elements of each group have the same number of electrons in their last atomic shell, which is why they have similar chemical properties, because the chemical properties of chemical elements are strongly related to the electrons located in the last atomic shell.

That is, in a group, the chemical properties are very similar, because all the elements of the group have the same number of electrons in their last or last shells.

<u><em>A barium atom would be expected to contain 2 electrons in its outer energy level.</em></u>

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A molecule of ethyl alcohol is converted to acetaldehyde in one’s body by zero order kinetics. If the concentration of alcohol i
Oliga [24]

Answer:

(1) 0.0016 mol/L

Explanation:

Let the concentration of alcohol after 3.5 hours be y M

The reaction follows a first-order

Rate = ky^0 = change in concentration/time

k = 6.4×10^-5 mol/L.min

Initial concentration = 0.015 M

Concentration after 3.5 hours = y M

Time = 3.5 hours = 3.5×60 = 210 min

6.4×10^-5y^0 = 0.015-y/210

y^0 = 1

0.015-y = 6.4×10^-5 × 210

0.015-y = 0.01344

y = 0.015 - 0.01344 = 0.00156 = 0.0016 mol/L (to 4 decimal places)

5 0
3 years ago
The process which plants use to make food is called:
riadik2000 [5.3K]
The answer is Photosynthesis!
5 0
4 years ago
Read 2 more answers
An equilibrium mixture contains 0.750 mol of each of the products (carbon dioxide and hydrogen gas) and 0.200 mol of each of the
sasho [114]

1.302  moles of carbon dioxide would have to be added

<h3>Further explanation</h3>

The equilibrium constant is the value of the product in the equilibrium state of the substance in the right (product) divided by the substance in the left (reactant) with the exponents of each reaction coefficient

The equilibrium constant is based on the concentration (Kc) in a reaction

pA + qB -----> mC + nD

\large {\boxed {\bold {Kc ~ = ~ \frac {[C] ^ m [D] ^ n} {[A] ^ p [B] ^ q}}}}

While the equilibrium constant is based on partial pressure

\large {\boxed {\bold {Kp ~ = ~ \frac {[pC] ^ m [pD] ^ n} {[pA] ^ p [pB] ^ q}}}}

The value of Kp and Kc can be linked to the formula '

\large {\boxed {\bold {Kp ~ = ~ Kc. (R.T) ^ {\Delta n}}}}

R = gas constant = 0.0821 L.atm / mol.K

=n = number of product coefficients-number of reactant coefficients

An equilibrium mixture: 0.750 moles of CO2 and H2, and 0.200 moles of CO and H2O

  • We determine Kc (constant concentration)

\displaystyle Kc=\frac{0.75.0.75}{0.2.0.2}\\\\Kc=14.1

  • the amount of carbon monoxide to 0.300 mol

Reaction :

                CO +H₂O ⇔ CO₂ + H₂

initially      0.2   0.2       0.75+x  0.75

reaction    0.1    0.1        0.1         0.1

product     0.3   0.3       0.65+x    0.65

\displaystyle Kc=\frac{(0.650+x)(0.65)}{0.3.0.3}\\\\14.1(0.09)=0.4225+0.65x\\\\1.269-0.4225=0.65x\\\\0.8465=0.65x\\\\x=1.302

<h3>Learn more</h3>

an equilibrium constant brainly.com/question/9173805

brainly.com/question/1109930

Calculate the value of the equilibrium constant, Kc

brainly.com/question/3612827

Concentration of hi at equilibrium

brainly.com/question/8962129

Keywords: constant equilibrium, Kc, concentration, product, reactant, reaction coefficient

3 0
4 years ago
Read 2 more answers
For the reaction below, determine the standard free energy change, δg o. cu(s) + sn2+(aq) → cu2+(aq) + sn(s) e o cell =–0.48 v v
Salsk061 [2.6K]

Answer:

92.6 kJ.

Explanation:

<em>∵ ΔG°rxn = - nFE°cell,</em>

Where, ΔG°rxn is the standard free energy change (J).

n is the no. of electrons in the reaction (n =2).

F is Faraday constant (C/mol) (F = 96500 C/mol).

E°cell is the standard cell potential (E°cell = - 0.48 V).

<em>∴ ΔG°rxn = - nFE°cell </em>= - (2)(96500 C/mol)(- 0.48 V) = <em>92640 J = 92.64 kJ.</em>

7 0
3 years ago
PLEASE HELP I CAN'T FIGURE IT OUT
laiz [17]

Answer:

11. F

12.H

16.J

20.K

21.i

Explanation:

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