At the library, 56 people borrowed

Mathematics

1 answer:

irina [24]2 years ago

5 0

Answer:

24 people borrowed the books on Friday

Step-by-step explanation:

Every day, the number of books is being subtracted by 2.

56 - Monday (-8)

48 - Tuesday (-8)

40 - Wednesday (-8)

32 - Thursday (-8)

24- Friday

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Please find the exact length of the midsegment of trapezoid JKLM with vertices J(6, 10), K(10, 6), L(8, 2), and M(2, 2). Thank y

I am Lyosha [343]

Answer:

the exact length of the midsegment of trapezoid JKLM = $\mathbf{ = 3 \sqrt{5} }$ i.e 6.708 units on the graph

Step-by-step explanation:

From the diagram attached below; we can see a graphical representation showing the mid-segment of the trapezoid JKLM. The mid-segment is located at the line parallel to the sides of the trapezoid. However; these mid-segments are X and Y found on the line JK and LM respectively from the graph.

Using the expression for midpoints between two points to determine the exact length of the mid-segment ; we have:

$\mathbf{ YX = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} }$

$\mathbf{ YX = \sqrt{(8-5)^2+(8-2)^2} }$

$\mathbf{ YX = \sqrt{(3)^2+(6)^2} }$

$\mathbf{ YX = \sqrt{9+36} }$

$\mathbf{ YX = \sqrt{45} }$

$\mathbf{ YX = \sqrt{9*5} }$

$\mathbf{ YX = 3 \sqrt{5} }$

Thus; the exact length of the midsegment of trapezoid JKLM = $\mathbf{ = 3 \sqrt{5} }$ i.e 6.708 units on the graph

8 0

2 years ago

If θ is an acute angle and sin θ = 2 1 , then cos θ =

ss7ja [257]

First of all i think theres a mistakein the question;
i think it is sin θ = $\frac{1}{2}$

and then sin 30° = $\frac{1}{2}$

thus θ= 30° $\frac{ \sqrt{3} }{2}$