For large sample confidence intervals about the mean you have:
xBar ± z * sx / sqrt(n)
where xBar is the sample mean z is the zscore for having α% of the data in the tails, i.e., P( |Z| > z) = α sx is the sample standard deviation n is the sample size
We need only to concern ourselves with the error term of the CI, In order to find the sample size needed for a confidence interval of a given size.
z * sx / sqrt(n) = width.
so the z-score for the confidence interval of .98 is the value of z such that 0.01 is in each tail of the distribution. z = 2.326348
The equation we need to solve is:
z * sx / sqrt(n) = width
n = (z * sx / width) ^ 2.
n = ( 2.326348 * 6 / 3 ) ^ 2
n = 21.64758
Since n must be integer valued we need to take the ceiling of this solution.
n = 22
Answer:
N'O' = 25
Step-by-step explanation:
N'O' = 5 × NO = 5 × 5 = 25
Well there are 6 units down and 11 units across so 6•11=66. there are 14 red units. 66-14=52. the area of yellow is 52.
If this pertains to the Pythagorean theorem, then the answer that you would most likely to end up with is by utilizing the equation a² + b² = c² where a and b are the legs of the triangle and c is the hypotenuse. The hypotenuse refer to the longest side of the triangle while the other two would be the legs of the triangle.
When solving for the missing length, just substitute the values given to their respective places in the equation. If a length of a leg is missing, then substitute the other leg's value to either a or b, then substitute the length of the hypotenuse to c. Then solve. Solving for the hypotenuse's length would be a lot easier than the legs.