The answer is 69.048%.
Mass of potassium dichromate (K₂Cr₂O₇) is 294 g, which is a 100%.
Given mass of chromium is 52 g. So, the mass percent of chromium in the compound is 17.687%:
52 g : x% = 294 g : 100%
x = 52 ÷ 294 × 100 %
x = 17.687%
Given mass of potassium is 39 g. <span>So, the mass percent of potassium in the compound is 13.265%:
39 g : x% = 294 g : 100%
x = </span>39 ÷ <span>294 × 100 %
x = 13.265%
Therefore, </span>the mass percent of oxygen in the compound is <span>69.048%:
100% - </span>17.687% - <span>13.265% = 69.048%.</span>
Answer:
Explanation:
Silver nitrate grams to moles
1 grams Silver Nitrate is equal to 0.0058867472248402 mole
Explanation:
Given parameters:
Mass of Br-79 = 78.918 amu
Abundance = 50.69%
Unknown:
Mass of Br - 81 = ?
Solution:
Relative Atomic mass of Br = 80
The proportion by which each fraction of an isotope occurs in nature is called the geonormal abundance.
RAM = Ma Ba + McBc
The formula above is used to find the average mass of the given isotopes.
Since we know the percentage abundance of Br-79, that of Br-81 = 100-50.69= 49.31%
RAM = Ma Ba + McBc
RAM = relative atomic mass
Ma Ba = mass and abundance of Br-79
McBc = mass and abundance of Br-81
80 = (78.918 x
) + (
x C)
80 = 40 + 0.49C
0.49C = 40
C =
= 81.63amu
learn more;
Isotopes brainly.com/question/10862182
#learnwithBrainly
Fungi and bacteria-- mushrooms, bacteria, mold...