What is the ph of a buffer that consists of 0.45 m ch3cooh and 0.35 m ch3coona? ka = 1.8 × 10–5?

Chemistry

1 answer:

oee [108]4 years ago

8 0

Answer is: pH of a buffer is 4.64.

ck(CH₃COOH) = 0.45 M.

cs(CH₃COONa) = 0.35 M.

Ka = 1.8·10⁻⁵.

pKa = -logKa.
pKa = -log(1.8·10⁻⁵) = 4.75.
Henderson–Hasselbalch equation: pH = pKa + log(cs/ck).
pH = 4.75 + log(0.35M/0.45M).
pH = 4.75 - 0.11.
pH = 4.64.

pH (potential of hydrogen) is a numeric scale used to specify the acidity or basicity an aqueous solution.

You might be interested in

What else is produced when sodium carbonate decomposes? Na2Co3 - Na2O+

AleksandrR [38]

Answer:When a single compound breaks down into two or more compounds or elements in a chemical reaction then it is known as decomposition reaction.

The chemical symbol for sodium carbonate is .

The decomposition of sodium carbonate is:

The decomposition of sodium bicarbonate, will result in the formation of sodium oxide, and carbon dioxide, .

Hence, carbon dioxide, will produce with sodium oxide, on decomposition of .

Explanation:Na2CO3 Na2O +CO2 CO2 is the answer

8 0

3 years ago

Help please !!!

nikklg [1K]

I believe the correct answer would be "It has no energy because it is just sitting there."

I hope this helps! :D

8 0