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2 years ago

How many elements make up Ibuprofen? C13H18O2

Chemistry

1 answer:

mylen [45]2 years ago

3 0

Answer:

Explanation:

wouldn't it be three because every capital is a new element?

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We measure force in units called

madam [21]

Force is measured in Newtons, which are units that equal 1 kg * m/sec 2. Force is measured in Newtons, N. Mass is measured in kilograms, kg. The unit that is used to measure force in the SI system of units is the Newton.

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3 years ago

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leonid [27]

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6 0

3 years ago

Calculate the number of moles in each sample. part a 76.1 g h2ccl2

Airida [17]

The number of moles in a substance may be calculated using:

Moles = mass / molecular mass

The molecular mass of CH₂Cl₂ is:
12 + 2 * 1 + 2 * 35.5
= 85 grams / mole

Moles = 76.1 / 85
Moles = 0.895

There are 0.90 moles of CH₂Cl₂ present in 76.1 grams.

3 0

4 years ago

6) A 14.5 g sample of sodium chloride reacts with excess fluorine gas according to

Ann [662]

The mass of chlorine gas produced by 14.5 grams of sodium chloride is 10.42 g.

The mass of chlorine gas produced by 14.5 grams of sodium chloride is 8.81 g.

The given parameters;

mass of the sodium chloride, = 14.5 g
2NaCl(s) + F2(g) → 2NaF(s) + Cl2(g)

In the reaction above, we can deduce the following;

molecular mass of 2Nacl = 2(58.44) = 116.88 g

molecular mass of 2NaF = 2(42) = 84 g

molecular mass of Cl2 = 71 g

The mass of sodium fluoride produced by 14.5 grams of sodium chloride is calculated as follows;

116.88 g of NaCl --------------- 84 g of NaF

14.5 g of NaCl ------------------- ?

$= \frac{84 \times 14.5}{116.88} \\\\= 10.42 \ g$

The mass of chlorine gas produced by 14.5 grams of sodium chloride is calculated as follows;

116.88 g of NaCl --------------- 71 g of Cl2

14.5 g of NaCl ------------------- ?

$= \frac{14.5 \times 71}{116.88} \\\\= 8.81 \ g$

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8 0

3 years ago

Given: C + O2 → CO2 Bond Bond Energy (kJ/mol) C=O 799 O=O 494 Calculate the enthalpy change for the chemical reaction. The chang

aliya0001 [1]

Answer:

-1104 kJ/mol

Explanation:

The change in the enthalpy of a reaction is equal to the difference between: the sum of the enthalpy changes of the bonds broken and the sum of the enthalpy changes of the bonds formed.

The bonds broken correspond to the cleavage of bonds of the reactants, the bonds formed correspond to the bonds of the products:

we only break oxygen O=O bond, since carbon is not bonded to anything;
we form two C=O bonds in carbon dioxide.

Therefore, the enthalpy change is calculated by:

$\Delta H^o = 1 mol\cdot 494 kJ/mol - 2 mol\cdot 799 kJ/mol = -1104 kJ/mol$

3 0

3 years ago