Answer:
Explanation:
Molarity is found by dividing the moles of solute by liters of solution.
We know the molarity is 1.2 M (mol\liter) and there are 2.3 liters of solution. Substitute the known values into the formula.
Since we are solving for x, we must isolate the variable. It is being divided by 2.3 and the inverse of division is multiplication. Multiply both sides by 2.3 liters.
In a solution with a molarity of 1.2 and 2.3 liters of solution, there are 2.76 moles.
Answer:
MgBr2
Explanation:
(Mg^2+) + (Br^1-)
For every Mg we need 2 Br to balance out the compound.
Answer:
The answer to your question is: 234.7 cans
Explanation:
data
caffeine concentration = 3.55 mg/oz
10.0 g of caffeine is lethal
there are 12 oz of caffeine in a can
Then
3.55 mg ----------------- 1 oz
x mg -----------------12 oz (in a can)
x = 42.6 mg of caffeine in a can
Convert it to grams 42,6 mg = 0.0426 g of caffeine in a can
Finally
0.0426 g of caffeine ------------------ 1 can
10 g of caffeine ----------------- x
x = 10 x 1/0.0436 = 234.7 cans
Answer:
S = 7.9 × 10⁻⁵ M
S' = 2.6 × 10⁻⁷ M
Explanation:
To calculate the solubility of CuBr in pure water (S) we will use an ICE Chart. We identify 3 stages (Initial-Change-Equilibrium) and complete each row with the concentration or change in concentration. Let's consider the solution of CuBr.
CuBr(s) ⇄ Cu⁺(aq) + Br⁻(aq)
I 0 0
C +S +S
E S S
The solubility product (Ksp) is:
Ksp = 6.27 × 10⁻⁹ = [Cu⁺].[Br⁻] = S²
S = 7.9 × 10⁻⁵ M
<u>Solubility in 0.0120 M CoBr₂ (S')</u>
First, we will consider the ionization of CoBr₂, a strong electrolyte.
CoBr₂(aq) → Co²⁺(aq) + 2 Br⁻(aq)
1 mole of CoBr₂ produces 2 moles of Br⁻. Then, the concentration of Br⁻ will be 2 × 0.0120 M = 0.0240 M.
Then,
CuBr(s) ⇄ Cu⁺(aq) + Br⁻(aq)
I 0 0.0240
C +S' +S'
E S' 0.0240 + S'
Ksp = 6.27 × 10⁻⁹ = [Cu⁺].[Br⁻] = S' . (0.0240 + S')
In the term (0.0240 + S'), S' is very small so we can neglect it to simplify the calculations.
S' = 2.6 × 10⁻⁷ M
Hello :)
Based on the information I received reading the picture, the answer should be “B”
Explanation: if I am wrong I’m very sorry. But that should be the answer
