Answer:
The required volume of hexane is 0.66245 Liters.
Explanation:
Volume of octane = v=1.0 L=
Density of octane= d =
Mass of octane ,m=
Moles of octane =
Mole percentage of Hexane = 45%
Mole percentage of octane = 100% - 45% = 55%
Total moles = 11.212 mol
Moles of hexane :
Moles of hexane = 5.0454 mol
Mass of 5.0454 moles of hexane,M = 5.0454 mol × 86 g/mol=433.9044 g
Density of the hexane,D =
Volume of hexane = V
(1 cm^3= 0.001 L)
The required volume of hexane is 0.66245 Liters.
The similarity between first quarter moon and third quarter moon, is the moon is located perpendicular to Earth and the sun.
<h3>What is first quarter moon?</h3>
The first quarter moon is a primary moon phase when half of the moon's face is lit up.
The first quarter moon rises around midday and is visible in the day sky.
<h3>What is third quarter moon?</h3>
Third quarter moon is when the opposite half of the moon is illuminated compared to the first quarter moon. It is the last quarter moon of a lunar month.
<h3>Similarity between
first quarter moon and third quarter moon?</h3>
The similarity between first quarter moon and third quarter moon, is the moon is located perpendicular to Earth and the sun.
Thus, the similarity between first quarter moon and third quarter moon, is the moon is located perpendicular to Earth and the sun.
Learn more about first quarter moon here: brainly.com/question/13435421
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Answer:What is used up in and stops a chemical reaction? (a) percent yield (b) limiting reactant (c) theoretical yield (d) excess reactant
The correct option is (b)
Explanation:
A chemical reaction is a chemical combination,rearrangement or disintegration of chemical substance(s) (called reactants) to form new chemical substance(s) (called products).
A limiting reactant is the reactant that is totally used up during the course of a reaction. When this reactant is used up, it limits the amount of products formed and eventually stops the chemical reaction.
Explanation:
The limiting reagent is the reactant that is used up completely. This stops the reaction and no further products are made. ... This method is most useful when there are only two reactants. The limiting reagent can also be derived by comparing the amount of products that can be formed from each reactant.
hope this helps have a nice day❤️
In the problem, we are tasked to solved for the amount of carbon (C) in the acetone having a molecular formula of C 3 H 6 O. We need to find first the molecular weight if Carbon (C), Hydrogen (H), Oxygen (O).
Molecular Weight:
C=12 g/mol
H=1 g/mol
O=16 g/mol
To calculate for the percent by mass of acetone, we assume 1 mol of acetone.
%C=
%C=62.07%
Therefore, the percent by mass of carbon in acetone is 62.07%
Answer:
518.52K
Explanation:
Charles law, which describes the direct relationship between the volume and the temperature of a gas when the pressure is constant, will be used for this question. The Charles law equation is:
V1/T1 = V2/T2
Where; V1 is the volume of the gas at an initial state (Litres)
T1 is the absolute temperature of the gas at an initial state (Kelvin)
V2 is the volume of the gas at a final state (Litres)
T2 is the absolute temperature of the gas at a final state (Kelvin)
According to the question, V1 = 2.3L, T1 = 25°C, V2 = 4L, T2 = ?
We need to convert the temperature to the absolute temperature unit in Kelvin (K) i.e.
T(K) = T(°C) + 273.15
T(K) = 25°C + 273.15
T1 (K) = 298.15K
To find for T2 in the equation, we make T2 the subject of the formula:
T2 = V2 × T1 / V1
T2 = 4 × 298.15 / 2.3
T2 = 1192.6/2.3
T2 = 518.52
Thus, the temperature must be heated to 518.52K in order to expand to a volume of 4L. This answer is in accordance to Charles law that the volume increases with increase in temperature and vice versa.