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Rainbow [258]
4 years ago
10

Which postulate of Dalton's atomic theory is the result of the law of conservation of mass

Chemistry
1 answer:
creativ13 [48]4 years ago
8 0

The postulate of Dalton's atomic theory which is a result of the law of conservation of mass is: Atoms are indivisible particles, which can neither be created nor destroyed in a chemical reaction.

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Describe how plants might be affected if the inter molecular forces in water decreased? i need asap!
vovangra [49]

Answer:

Water has polar O-H bonds. The negative O atoms attract the positive H atoms in nearby molecules, leading to the unusually strong type of dipole-dipole force called a hydrogen bond. Since water has hydrogen bonds, it also has dipole-induced dipole and London dispersion forces.

Hope it helped!!

6 0
3 years ago
An atom with 2 protons 3 neutrons and 2 electrons has a charge of
V125BC [204]

Answer: It has a charge of -2 because it has 2 more electrons than protons meaning it has a negative charge of 2 which is -2. Neutrons don't effect charge.

( +1 +1 -1 -1 -1 -1) = -2

Each proton has a charge of +1 and each electron has -1.

2(1) - 4(1) = -2

Explanation:

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4 0
3 years ago
This is the balanced chemical equation for a reaction
Gekata [30.6K]

Answer: C

Explanation:

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7 0
3 years ago
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If 7.84 × 107 J of energy is released from a fusion reaction, what amount of mass in kilograms would be lost? Recall that c = 3
yanalaym [24]
The correct answer would be 8.71 × 10<span>–10</span>
6 0
3 years ago
Swer all parts. (a) What is the wavelength (in nm) of radiation that has an energy ...
bagirrra123 [75]

Answer:

a) The wavelength is around 33.8 nm = 3.38*10⁻¹ nm

b) Ultraviolet

Explanation:

a) The energy (E) of a photon is related to its wavelength (λ) by the Planck's equation:

E = h\frac{c}{\lambda}----(1)

where h = Planck's constant = 6.626*10^-34 Js

c = speed of light = 3*10^8 m/s

E = 3.55*10^6 J/mol

The energy in terms of J/photon is:

=\frac{3.55*10^{6} J/mol*1mol}{6.023*10^{23} photons } =5.89*10^{-18} J/photon

Based on eq(1)

\lambda = h\frac{c}{E}=6.626*10^{-34}Js*\frac{3*10^{8}m/s}{5.89*10^{-18}J}=3.38*10^{-8}m

The wavelength is around 33.8 nm = 3.38*10⁻¹ nm

b) In the electromagnetic spectrum the ultraviolet range extends from 390 nm-8.82 nm

The calculated wavelength of 33.8 nm should fall in the UV range.

5 0
3 years ago
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