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quester [9]
4 years ago
15

Calculate the mass in grams 3.00 moles Na

Chemistry
1 answer:
exis [7]4 years ago
8 0

hmm looks like u gotta divide 3 by 2.9

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Where in the lungs does gas exchange occur
Lina20 [59]

Answer: Between the alveoli and a network of tiny blood vessels called capillaries, which are located in the walls of the alveoli.

7 0
3 years ago
Give the Unabbreviated electron configuration for barium
Shalnov [3]

Answer:

Ba: 1s² 2s²2p⁶ 3s²3p⁶ 4s²3d¹⁰4p⁶ 5s²4d¹⁰5p⁶ 6s²

Step-by-step explanation:

Step 1. Locate barium in the Periodic Table.

It's in Period 6, Group 2: Element 56 (highlighted blue in the Periodic Table below).

Step 2. Add 54 electrons to the energy levels

You add then in the order shown in the diagram below.

The complete electron configuration is:

Ba: 1s² 2s²2p⁶ 3s²3p⁶ 4s²3d¹⁰4p⁶ 5s²4d¹⁰5p⁶ 6s²

n =  2 +     8    +    8     +       18       +       18       +  2 = 56

8 0
3 years ago
16. The structure shown is representative of which substituted hydrocarbon?
Viktor [21]

Answer:

The answer is B. Ether

Explanation:

An atom of Oxygen between a carbon chain is called Ether

5 0
3 years ago
The mole fraction of nitrogen in the air is 0.7808. this means that 78.08% of the molecules in the air are nitrogen. when the at
Pachacha [2.7K]

Answer:

p = \boxed{\text{593 torr}}

Explanation:

For this question, we must use Dalton's Law of Partial Pressures:

The partial pressure of a gas in a mixture of gases equals its mole fraction times the total pressure:

p = \chi p_{\text{tot}}

Data:

χ = 0.7808

p_{\text{tot}} = \text{ 760 torr}

Calculation:

p = 0.7808 \times \text{ 760 torr}\\\\p= \boxed{\textbf{593 torr}}

7 0
3 years ago
How much water should be added to 85 mL of 0.45 M HCI to reduce the concentration to 0.20 M?
valkas [14]

Answer:

106.25 mL

Explanation:

For this, we can use

C1×V1=C2×V2

C1 = 0.45

V1 = 85

C2= 0.20

V2= ?

0.45 × 85 = 0.20 × V2

V2= (0.45 × 85)/0.20

V2=191.25mL

To find the amount of water added, subtract V1 from V2

191.25 - 85 =106.25mL

8 0
3 years ago
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