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hjlf
3 years ago
9

Which of the following is a small-scale, sudden natural change?

Chemistry
1 answer:
stellarik [79]3 years ago
7 0
D because yes it works very slow 
You might be interested in
What pressure, in atm, is exerted by 2.50 L of gas containing 1.35 mol at 320 K?
salantis [7]

Answer:

Option A = 14.19 atm

Explanation:

Given data:

Volume of gas = 2.50 L

Number of moles of gas = 1.35 mol

Temperature of gas = 320 K

Pressure of gas = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will put the values in formula.

P × 2.50 L =  1.35 mol × 0.0821 atm.L/ mol.K×   320

P = 35.467 atm.L/ 2.50 L

P = 14.19 atm

Thus, option A is correct.

6 0
3 years ago
The Prandtl number, Npr, is a dimensionless group important in heat transfer calculations. It defined as Cuk, where C, is the he
VARVARA [1.3K]

Answer:

The Prandlt number for this fluid is 1630.

Explanation:

The Prandlt number is defined as:

Pr=\frac{C_p\mu}{k}

To compute the Prandlt number for this case, is best if we use the same units in every term of the formula.

\mu=1936\frac{lb}{ft*h}*\frac{1000g}{2.205lb}*\frac{3.281ft}{1m}*\frac{1h}{3600s}  \\ \\\mu=800 \frac{g}{m*s}

Now that we have coherent units, we can calculate Pr

Pr=\frac{C_p\mu}{k}=\frac{0.583*800}{0.286}= 1630

8 0
3 years ago
Table B: Enthalpy of Formation of Reactants and Products
Inessa [10]

The calculated enthalpy values are as follows:

  • Total enthalpy of reactants = -103.85 KJ/mol
  • Total enthalpy of products = -2057.68 KJ/mol
  • Enthalpy of reaction = -1953.83 kJ/mol

<h3>What is the enthalpy of the reaction?</h3>

The enthalpy of the reaction is determined as follows:

  • Enthalpy of reaction = Total enthalpy of products -Total enthalpy of reactants
  • Total enthalpy of reactants = (ΔHf of Reactant 1 x Coefficient) + (ΔHf of Reactant 2 x Coefficient)
  • Total enthalpy of products= (ΔHf of Product 1 x Coefficient) + (ΔHf of Product 2 x Coefficient)

Equation of reaction equation: C₃H₈ (g) + 5 O(g) → 4 H₂O(g) + 3CO₂(g)

Total enthalpy of reactants = (-103.85 * 1) + (0 * 5)

Total enthalpy of reactants = -103.85 + 0

Total enthalpy of reactants = -103.85 KJ/mol

Total enthalpy of products = (-393.51 * 4) +(-241.82 * 3)

Total enthalpy of products = (-1574.04) + (-483.64)

Total enthalpy of products = -2057.68 KJ/mol

Enthalpy of reaction =  -2057.68 KJ/mol -(-103.85 KJ/mol)

Enthalpy of reaction = -1953.83 kJ/mol

In conclusion, the enthalpy of the reaction is determined from the difference between the total enthalpy of products and reactants.

Learn more about enthalpy of reaction at: brainly.com/question/14047927

#SPJ1

5 0
1 year ago
Which statement about forces is true?
Elodia [21]

Answer:

c

Explanation:

because forces act on an object and make it change direction based upon strength hope this helps.

4 0
3 years ago
What are the two types of passive transport
sladkih [1.3K]
They are DIFFUSION and OSMOSIS.
8 0
3 years ago
Read 2 more answers
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