Question

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A number, p, varies directly as q and partly inversely as q${}^{2}$. Given that p = 11 and q = 7 and p = 25.16 when q = 5, calculate the value of p when q = 7​​

Answer 1

Answer:

p = kq + m(1/q^2)

where k and m are constants....

then you form simultaneous equation.....

use elimination method to find the constant k and m...

use the constant to find value of p, when q is 7