Answer:
Acceleration of object=
Explanation:
Given:-
Velocity (v)=24 cm/s
Time (t)=3 s
To calculate acceleration (a) of object=?
Now,
Therefore object acceleration =
Forces always work in the direction of their application.
Eg- Gravitational forces acts downwards due to the earth's pull.
Answer:
The 10-meter long rod of an SR-71 airplane expands 0.02 meters (2 centimeters) when plane flies at 3 times the speed of sound.
Explanation:
From Physics we get that expansion of the rod portion is found by this formula:
(Eq. 1)
Where:
- Expansion of the rod portion, measured in meters.
- Linear coefficient of expansion for titanium, measured in 
.
- Initial length of the rod portion, measured in meters.
- Initial temperature of the rod portion, measured in Celsius.
- Final temperature of the rod portion, measured in Celsius.
If we know that 
, 
, 
and 
, the expansion experimented by the rod portion is:
The 10-meter long rod of an SR-71 airplane expands 0.02 meters (2 centimeters) when plane flies at 3 times the speed of sound.
Answer:
* energy is proportional to masses. in a graph it would look like a line
* kinetic energy varies with the square of the velocity, In a graph it gives rise to a quadratic curve
Explanation:
Kinetic energy is defined by
K = ½ m v²
when analyzing this expression we can see:
* energy is proportional to masses. Therefore, doubling the mass doubles the kinetic energy and if the mass rises 4 times the energy rises 4 times, that is, they are directly proportional, in a graph it would look like a line
* kinetic energy varies with the square of the velocity. Therefore by doubling the speed the energy goes up 4 times. In a graph it gives rise to a quadratic curve
Answer:
2.1 rad(anticlockwise).
Explanation:
So, we are given the following data or parameters or information in the question above:
=> "The torsional stiffness of the spring support is k = 50 N m/rad. "
=> "If a concentrated torque of mag- nitude Ta = 500 Nm is applied in the center of the bar"
=> "L = 300 mm Assume a shear modu- lus G = 10 kN/mm2 and polar monnent of inertia J = 2000 mln"
Hence;
G × J = 10 kN/mm2 × 2000 mln = 20 Nm^2.
Also, L/2 = 300 mm /2 = 0.15 m (converted to metre).
==> 0.15/20 (V - w) + θ = 0.
==> 0.15/20 (V - w ) = -θ.
Where V = k = 50 N m/rad
w = 183.3 θ.
Therefore, w + Vθ = 500 Nm.
==> 183.3 + 50 θ = 500 Nm.
= 6.3
Anticlockwise,
θ = 2.1 rad.
